（批处理）如何将输出重定向应用于一行的最后一个程序？
我在批处理脚本中有一行，我想从中捕获输出。我想将其重定向到一个文件。我的问题是该行中有 3 个程序，每个程序都调用下一个程序。这是一行：
start cmd /C java -jar Prog.jar -remote %1.xml > ProgOut.txt
目前，我的猜测是 '>'应用于启动，而我想获得java的输出（我实际上得到一个空文件，如果它是java输出，这是不可能的）...我尝试在java部分周围有“”，但它显然没有不工作。我想在另一个批处理文件中使用 java 命令可以解决我的问题，但如果可能的话，我宁愿不重复脚本文件。
谢谢！
I have a line, in a batch script, from which I would like to capture the output. I would like to redirect it to a file. My problem is that there are 3 programs in that line, each calling the next. Here is the line:
start cmd /C java -jar Prog.jar -remote %1.xml > ProgOut.txt
At the moment, my guess is that the '>' is applied to start, while I would like to get the output of java (I actually get an empty file which is impossible if it is the java output)... I have tried having "" around the java part, but it obviously didn't work. I suppose that having the java command in another batch file would fix my problem, but I'd rather not duplicate script files, if possible.
Thanks!
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您的批处理文件将如下所示：
找到此： http://www.windowsitpro.com/article/tips/jsi-tip-7733-how- do-i-redirect-the-output-of-a-program-that-i-launched-with-the-start-command-.aspx
Your batch file would look like this:
Found this on: http://www.windowsitpro.com/article/tips/jsi-tip-7733-how-do-i-redirect-the-output-of-a-program-that-i-launched-with-the-start-command-.aspx