C++ TR1 正则表达式 - 多行选项
我认为 $ 表示字符串的结尾。然而，下面的代码给出了“testbbbccc”作为结果，这对我来说非常令人惊讶......这意味着 $ 实际上匹配行尾，而不是整个字符串的结尾。
#include <iostream>
#include <regex>
using namespace std;
int main()
{
tr1::regex r("aaa([^]*?)(ogr|$)");
string test("bbbaaatestbbbccc\nddd");
vector<int> captures;
captures.push_back(1);
const std::tr1::sregex_token_iterator end;
for (std::tr1::sregex_token_iterator iter(test.begin(), test.end(), r, captures); iter != end; )
{
string& t1 = iter->str();
iter++;
cout << t1;
}
}
我一直在尝试找到一个“多线”开关（实际上可以在 PCRE 中轻松找到），但没有成功......有人可以指出我正确的方向吗？
问候， RP
I thought that $ indicates the end of string. However, the following piece of code gives "testbbbccc" as a result, which is quite astonishing to me... This means that $ actually matches end of line, not end of the whole string.
#include <iostream>
#include <regex>
using namespace std;
int main()
{
tr1::regex r("aaa([^]*?)(ogr|$)");
string test("bbbaaatestbbbccc\nddd");
vector<int> captures;
captures.push_back(1);
const std::tr1::sregex_token_iterator end;
for (std::tr1::sregex_token_iterator iter(test.begin(), test.end(), r, captures); iter != end; )
{
string& t1 = iter->str();
iter++;
cout << t1;
}
}
I have been trying to find a "multiline" switch (which actually can be easily found in PCRE), but without success... Can someone point me to the right direction?
Regards,
R.P.
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由于为 tr1 选择了 Boost::Regex，请尝试以下操作：
来自 Boost::Regex
所以你观察到的行为是正确的。
来自： Boost 正则表达式 还有：
我希望有所帮助。
As Boost::Regex was selected for tr1, try the following:
From Boost::Regex
So the behavior you observed is correct.
From: Boost Regex as well:
I hope that helps.
TR1 正则表达式中没有多行开关。它并不完全相同，但您可以获得匹配所有内容的相同功能：
这会非贪婪匹配每个字符，包括换行符和回车符。
注意：如果您的模式是代码中的 C++ 字符串，请记住像
'\\'一样转义反斜杠'\'。注2：如果不想捕获匹配的内容，请在左括号后添加“?:”：
There is no multiline switch in TR1 regexs. It's not exactly the same, but you could get the same functionality matching everything:
This matches non-greedily every character, including new line and carriage return.
Note: Remember to escape the backslashes
'\'like this'\\'if your pattern is a C++ string in code.Note 2: If you don't want to capture the matched contents, append '?:' to the opening bracket: