如何查找完全位于两个指定节点之间的节点

发布于 2024-10-07 05:40:53 字数 595 浏览 2 评论 0原文

在如下所示的 XML 文档中：

<root>
  <fish value="Start"/>
  <pointlessContainer>
    <anotherNode value="Pick me!"/>
    <anotherNode value="Pick me too!"/>
    <fish value="End"/>
  </pointlessContainer>
</root>

如何使用 LINQ to XML 的神奇功能来查找 fish 节点完全包含的任何节点？请注意，在此示例中，我特意将 fish 节点放置在文档中的不同级别，因为我预计这种情况会在野外发生。

显然，在这个示例中，我希望获取两个 anotherNode 节点，而不是 pointlessContainer 节点。

注意：两个“定界”节点可能与文档中的其他非定界节点具有相同的类型（例如fish），但它们将具有唯一的属性，因此易于识别。

原文

In a XML document such as the following:

<root>
  <fish value="Start"/>
  <pointlessContainer>
    <anotherNode value="Pick me!"/>
    <anotherNode value="Pick me too!"/>
    <fish value="End"/>
  </pointlessContainer>
</root>

How can I use the wonder of LINQ to XML to find any nodes completely contained by the fish nodes? Note that in this example, I have deliberately placed the fish nodes at different levels in the document, as I anticipate this scenario will occur in the wild.

Obviously, in this example, I would be looking to get the two anotherNode nodes, but not the pointlessContainer node.

NB: the two 'delimiting' nodes may have the same type (e.g. fish) as other non-delimiting nodes in the document, but they would have unique attributes and therefore be easy to identify.

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倒带 2024-10-14 05:40:53

对于您的示例，应该执行以下操作，

        XDocument doc = XDocument.Load(@"..\..\XMLFile2.xml");
        XElement start = doc.Descendants("fish").First(f => f.Attribute("value").Value == "Start");
        XElement end = doc.Descendants("fish").First(f => f.Attribute("value").Value == "End");
        foreach (XElement el in 
            doc
            .Descendants()
            .Where(d => 
                XNode.CompareDocumentOrder(d, end) == -1 
                && XNode.CompareDocumentOrder(d, start) == 1 
                && !end.Ancestors().Contains(d)))
        {
            Console.WriteLine(el);
        }

但我还没有测试或彻底思考它是否适用于其他情况。也许您可以检查一些示例数据并报告其是否有效。

For your sample, the following should do

        XDocument doc = XDocument.Load(@"..\..\XMLFile2.xml");
        XElement start = doc.Descendants("fish").First(f => f.Attribute("value").Value == "Start");
        XElement end = doc.Descendants("fish").First(f => f.Attribute("value").Value == "End");
        foreach (XElement el in 
            doc
            .Descendants()
            .Where(d => 
                XNode.CompareDocumentOrder(d, end) == -1 
                && XNode.CompareDocumentOrder(d, start) == 1 
                && !end.Ancestors().Contains(d)))
        {
            Console.WriteLine(el);
        }

But I haven't tested or thoroughly pondered whether it works for other cases. Maybe you can check for some of your sample data and report back whether it works.

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