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只是 UIPickerView 中的数字？

发布于 2024-10-06 19:11:26 字数 85 浏览 2 评论 0原文

有没有办法让 UIPickerView 将数字递增到无穷大？哈哈。开玩笑，但说真的，我只想要一堆数字上升，但我不想全部硬编码。

提前致谢！

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放血 2024-10-13 19:11:28

我很确定这可以通过一些技巧来完成（一个自定义整数类，支持任意大的数字，并且一旦用户滚动所有 NSIntegerMax 行（即当用户滚动时）定期“滚动”到更高的数字集要行 NSIntegerMax，您以编程方式将它们滚动回第 0 行并显示“row + NSIntegerMax”，而不仅仅是“row”）。当它们重复滚动时，您将其更改为“row + NSIntegerMax * 2”等。

显然，您还必须这样做但我怀疑这比你想要做的更花哨

，在这种情况下，你只想将这些代码行添加到你的视图控制器中：

- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component {
    return NSIntegerMax;
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {
    return [NSString stringWithFormat:@"%d", row];
}

然后双击视图 nib 文件（ *.xib 文件）以在 Interface Builder 中打开它，并将“数据源”出口连接到“文件所有者”（视图控制器），这将为您提供我能想象到的尽可能多的整数。

I'm pretty sure this can be done with some cleverness (a custom integer class that supports arbitrarily large numbers, and periodically "rolling over" to a higher set of numbers once the user has scrolled through all NSIntegerMax rows (i.e. when the user scrolls to row NSIntegerMax you programmatically scroll them back to row 0 and display "row + NSIntegerMax" instead of just "row"). As they scroll through repeatedly you change it to "row + NSIntegerMax * 2", etc.

Obviously you also have to handle them changing directions are some point.

But I suspect that's what fancier than what you're looking to do. In this case you just want to add these lines of code to your View Controller:

- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component {
    return NSIntegerMax;
}

- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {
    return [NSString stringWithFormat:@"%d", row];
}

Then double click on the View nib file (the *.xib file) to open it in Interface Builder, and connect the "data source" outlet to the "File Owner" (the View Controller). That will get you as many integers as I could ever imagine someone scrolling to.

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