如何使用 XmlWriter/XmlReader 读取/写入复杂对象

发布于 2024-10-06 19:00:04 字数 542 浏览 4 评论 0原文

我一直在尝试找到一种使用 XmlReader/XmlWriter 编写 XML 的简单方法。我不太喜欢使用“IXmlSerialized”接口，但我对某些数据类别无选择。

不管怎样，我想做的很简单：

private MyClass myObject;
public void WriteXml(XmlWriter writer)
{
    writer.WriteObject(myObject); // <-- this method doesn't exists
}

所以，我找到了两个解决方法：

编写我自己的例程来手动编写我的对象。非常荒谬，因为 .Net 已经做到了。
使用 StringWriter 创建一个新的序列化程序并使用 WriteValue(string) 方法。

我还没有测试第二个，但我认为它可能会起作用（由于 ReadValue 结果而不确定）。

然后我的问题是：我是否错过了一些重要的事情或者这是唯一的方法？或者有更好的方法来处理吗？

谢谢。

原文

I've been trying to find an easy way to write XML using the XmlReader/XmlWriter. I don't really like using the interface "IXmlSerializable", but I've got no choice for some of my dataclass.

Anyway, what I want to do is quite simple:

private MyClass myObject;
public void WriteXml(XmlWriter writer)
{
    writer.WriteObject(myObject); // <-- this method doesn't exists
}

So, I found 2 work around:

Write my own routine to write my object manually. Quite ridiculous since .Net already does it.
Create a new serializer using a StringWriter and use the WriteValue(string) method.

I haven't tested the second yet but I think it will probably work (not sure because of the ReadValue result).

Then my question is: Am I missing something important or is it the only way? Or is there a better way to handle that?

Thanks.

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飘落散花 2024-10-13 19:00:04

经过一番尝试，我发现事情很简单。这是我正在为那些想知道如何解决我的问题的人使用的代码（类似于阅读和元素）：

    public static void WriteElement(XmlWriter writer, string name, object value)
    {
        var serializer = new XmlSerializer(value.GetType(), new XmlRootAttribute(name));
        serializer.Serialize(writer, value);
    }

我不知道为什么我使问题复杂化，但它不能比这更简单。

After playing around, I found something quite simple. Here is the code I was playing with for those who are wondering how I fixed my problem (similar for reading and element):

    public static void WriteElement(XmlWriter writer, string name, object value)
    {
        var serializer = new XmlSerializer(value.GetType(), new XmlRootAttribute(name));
        serializer.Serialize(writer, value);
    }

I don't know why I was complicating the problem, but it cannot be more simpler than that.

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