Zend 正则表达式路线帮助
我正在尝试创建一个 Zend_Controller_Router_Route_Regex 路由来处理以下形式的 URL：
search?q=chicken/page=2 其中第一个正则表达式子模式是 chicken ，第二个是将是2。至于第二部分，其中page=2，如果是第一页，我想将其设为可选，即page=1。因此，另一个 url（例如 search?q=chicken）也是有效的，并且等同于 search?q=chicken/page=1。
这是我的尝试，尽管没有成功，但可以让您更好地了解我正在尝试做的事情。
$route = new Zend_Controller_Router_Route_Regex(
'search\?q=([a-zA-Z0-9]+)(?:/page=(\d+))',
array(
'page'=> '1',
'module' => 'default',
'controller' => 'search',
'action' => 'index' ),
array( 1 => 'query', 2 => 'page' ),
'search?=%s/page=%d');
$router->addRoute('search', $route);
这里的问题是我无法编写正确的正则表达式。
提前致谢。
编辑 #1
正如 MA4 所指出的，正确的正则表达式是 'search\?q=([a-zA-Z0-9]+)(?:/page=(\d+))?'
Darryl 指出了真正的问题。这里有更多信息可以帮助您正确看待事情。
我的搜索文本框和按钮
<form action="/search" method="get">
<input type="text" name="q" />
<input type="submit" value="Search" />
</form>
每次按下 search 按钮时，我都会收到 search?q=[text] 请求。如何强制它通过正则表达式匹配路线？
这是我想做的，但是代码不起作用
if($this->getRequest()->getParam('query')){
// redirect success
} else {
$url = "search?q=" . $this->_getParam('q');
$this->_redirect(route('search'), array('code' => 301 ));
}
I am trying to create a Zend_Controller_Router_Route_Regex route to process URLs in the following form:
search?q=chicken/page=2 where the first regex subpattern would be chicken and second one would be 2. As for the second part where page=2, I want to make it optional if it is the first page, that is page=1. So another url such as search?q=chicken would also be valid and is equivalent to search?q=chicken/page=1.
Here is my attempt albeit without any success, but to give you a better picture of what I am trying to do.
$route = new Zend_Controller_Router_Route_Regex(
'search\?q=([a-zA-Z0-9]+)(?:/page=(\d+))',
array(
'page'=> '1',
'module' => 'default',
'controller' => 'search',
'action' => 'index' ),
array( 1 => 'query', 2 => 'page' ),
'search?=%s/page=%d');
$router->addRoute('search', $route);
The problem here is I cant compose the correct regex.
Thanks in advance.
EDIT #1
The correct regex, as pointed out by MA4, is 'search\?q=([a-zA-Z0-9]+)(?:/page=(\d+))?'
The real problem is pointed by Darryl. Here is a little bit more info to put things into perspective.
My search text box and button
<form action="/search" method="get">
<input type="text" name="q" />
<input type="submit" value="Search" />
</form>
Every time I press the search button, I get the search?q=[text] request. How do I force it to go through the regex match route?
Here is what i want to do, however the code does not work
if($this->getRequest()->getParam('query')){
// redirect success
} else {
$url = "search?q=" . $this->_getParam('q');
$this->_redirect(route('search'), array('code' => 301 ));
}
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评论（2）
/search?q=chicken/page=2无法被 Zend Frameworks 的路由器解析。路由器只会看到/search。路由器依赖于服务器提供的路径信息以及 ? 之后的任何内容。是查询字符串。
您需要使用这样的路径：
在这种情况下，您的正则表达式会变得更加简单。
/search?q=chicken/page=2is not parsable by Zend Frameworks' router. The router will only see/search.The router relies on the Path Info provided by the server and anything after the ? is the query string.
You would need to use a path such as this:
In which case your regex would become much simpler.
通过在其后添加
?使第二部分成为可选：make the second part optionnal by adding a
?after it: