相互引用的结构
我想要两个可以相互包含的结构。这是一个例子：
struct a {
struct b bb;
};
struct b {
struct a aa;
};
但是这段代码无法编译。 gcc 说：
test.c:3: error: field ‘bb’ has incomplete type
有办法实现这一点吗？
I want to have two structs that can contain each other. Here is an example:
struct a {
struct b bb;
};
struct b {
struct a aa;
};
But this code doesn't compile. gcc says:
test.c:3: error: field ‘bb’ has incomplete type
Is there a way to achieve this?
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那应该如何运作？
a将包含b，其中将包含a，其中将包含b等等...我想你想改用指针吗？
即使这是不好的编码风格 - 如果可能的话应该避免循环依赖。
How is that supposed to work?
awould containb, which would containa, which would containb, etc...I suppose you want to use a pointer instead?
Even that though is bad coding style - circular dependencies should be avoided if possible.
大多数头文件在定义其成员之前声明结构。结构定义将在其他地方定义。
Most of the header file declare the structure before defining its members. Structure definition will be defined in somewhere else.
处理这个问题的通常方法是使它们成为指针，然后动态分配它们，甚至只是从另一个结构的静态实例的地址分配指针。
不过，我建议您寻找树形结构的组织。也许这两个对象都可以指向共同的第三种类型。
The usual way of dealing with this is to make them pointers and then dynamically allocate them or even just assign the pointer from the address of a static instance of the other struct.
I would suggest, however, that you look for a tree-structured organization. Perhaps both objects could point to a common third type.
这是无稽之谈。
想象一下，如果您说每个
X都包含一个Y并且每个Y都包含一个X，那么在每个>X是一个Y，它又包含一个X，后者又包含一个Y，后者又包含一个 < code>X，无限。相反，您可以让
X包含对Y的引用或（或指向）Y，反之亦然 -反之亦然。This is nonsensical.
Imagine if you say that every
Xcontains aYand everyYcontains anX, then inside eachXis aYwhich in turn contains anX, which in turn contains aY, which in turn contains anX, ad infinitum.Instead, you can have an
Xcontain a reference to or (or pointer to) aYand vice-versa.