kSOAP2 输出 / org.xmlpull.v1.xmlpullparserexception 预期 start_tag

Question

我有一个标准代码来调用.net webservice，

我在行中得到Exception“org.xmlpull.v1.xmlpullparserexception Expected start_tag”

transportSE.call(SOAP_ACTION,soapSerializationEnvelope);

但是，如果我从以下位置调用相同的Web服务.NET 代码 我根据需要得到了结构良好的正确输出。

主要看起来，从 kSOAP2 中，它得到了明确的输出，但是当它进一步解析 SoapPrimitive 对象时，它会失败。

那么，是否有其他方法可以查看收到的实际输出（实际肥皂信封），然后可以自己适当地解析它。

Answer 1

我正在调查我遇到的类似问题。无意中看到这条评论

当我使用 SoapEnvelope.VER11 时，它工作正常，但是当我使用
SoapEnvelope.VER12，它给我错误：
“org.xmlpull.v1.XmlPullParserException：预期：START_TAG”。

http://groups.google.com/group/android-developers/browse_thread /thread/b585862b6e939fd2

也许我们遇到了有关肥皂版本的兼容性问题。另外，连接到 .net 服务时，您可能需要设置 envelope.dotNet = true; ..但您可能已经这样做了

Answer 2

我收到此 START_TAG 异常，但就我而言，这是因为我的值

METHOD_NAME="";
NAMESPACE ="";      
SOAP_ACTION ="";
URL ="";

不正确。

现在如何找出这些参数的正确值，您可以在此处查看我的其他答案

SoapObject req = new SoapObject(NAMESPACE,METHOD_NAME);
            //SoapObject req = new SoapObject(Namespace_Server,MethodName_Server);

    //req.addProperty("ImageData", Base64.encode(data));
    req.addProperty("ImageData", data);
    req.addProperty("login", CommonStaticData.getusername());
    req.addProperty("password",CommonStaticData.getpassword());
    req.addProperty("recipeId",FileID);

    MarshalBase64 mbase = new MarshalBase64();// marshal is used to serialize the byte array

    SoapSerializationEnvelope envelop = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelop.bodyOut = req;
    envelop.encodingStyle = SoapSerializationEnvelope.ENC2001;
    envelop.dotNet = true;
    envelop.setOutputSoapObject(req);


    HttpTransportSE aht = new HttpTransportSE(URL);

    mbase.register(envelop);


    aht.call(SOAP_ACTION,envelop);

Answer 3

现在我已经解决了我原来的问题，现在就来解决这个问题吧！

我发现 ksoap2 无法解析响应...特别是 org.kxml2.io.KXmlParser.require(type, namespace, name) 抛出以下异常。

WARN/System.err(2330): org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://www.w3.org/2001/12/soap-envelope}Envelope (position:START_TAG <h1>@1:4 in java.io.InputStreamReader@47ff3050) 

请注意 h1 标签。这来自

404 Not Found

...所以是的，请注意您的回复可能来自网站，而不是您的网络服务:)

希望有一天能对某人有所帮助

Answer 4

我遇到了几乎相同的错误，我的例外是“position:START_TAG @2:7”，

但我已经修复了，因为我以错误的方式命名了参数，该名称必须与 XSD 上指定的名称完全相同。

     SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
     request.addProperty("arg0_java_lang_String", "Club");

在 addPropery 方法中，我使用了错误的参数名称。

Answer 5

使用下面的代码，通过观察变量 urlc.getResponseCode() 的响应代码来确保 Web 服务的 url 可访问，同时将IP从localhost、fixed、external最后更改为10.0.2.2

public static boolean isNetworkAvailable() {
//http://stackoverflow.com/questions/1560788/how-to-check-internet-access-on-android-inetaddress-never-timeouts/4009133#comment24565402_4009133
        /* ConnectivityManager cm =
                    (ConnectivityManager) _context.getSystemService(Context.CONNECTIVITY_SERVICE);
                NetworkInfo netInfo = cm.getActiveNetworkInfo();
                if (netInfo != null && netInfo.isConnected()) {//netInfo.isConnectedOrConnecting()
                    return true;
                }
                return false;*/

//http://stackoverflow.com/questions/5474089/how-to-check-currently-internet-connection-is-available-or-not-in-android?rq=1             
                boolean connected = false;
                ConnectivityManager connectivityManager = (ConnectivityManager)_context.getSystemService(Context.CONNECTIVITY_SERVICE);
                    if(connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE).getState() == NetworkInfo.State.CONNECTED || 
                            connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI).getState() == NetworkInfo.State.CONNECTED) {
                        //we are connected to a network
                        connected=true;
                        return connected;
                    }
                    else
                        {
                        connected=false;
                        return false;
                        }
    }

    public static boolean hasActiveInternetConnection() {
        if (isNetworkAvailable()) {
            try {
                //String url = "http://www.google.com",
                String url = "http://10.0.2.2:8089/UNIV_AXIS_DYN_WEB/services/ServiceMethods?wsdl",
                        proxy = "proxy.rss.jo",
                        port= "8080";
                URL server = new URL(url);
                Properties systemProperties = System.getProperties();
                /*systemProperties.setProperty("http.prosyHost",proxy);
                systemProperties.setProperty("http.prosyHost",port);*/
                HttpURLConnection urlc = (HttpURLConnection) (server.openConnection());
                urlc.setRequestProperty("User-Agent", "Test");
                urlc.setRequestProperty("Connection", "close");
                urlc.setConnectTimeout(500); 
                urlc.connect();
                System.out.println(urlc.getResponseCode());
                return (urlc.getResponseCode() == 200);
            } catch (IOException e) {
                Log.e(LOG_TAG, "Error checking internet connection", e);
                return false;
            }
        } else {
            Log.d(LOG_TAG, "No network available!");
            return false;
        }

    }

对我来说，我得到了这个提示“不是下面缺少的字符s”

[错误] 尝试调用服务方法登录时发生异常
org.apache.axis2.AxisFault: 命名空间不匹配需要 http://services.univ.rss 找到 http://service.univ.rss

日志 tomcat 等的其余部分

at org.apache.axis2.rpc.receivers.RPCUtil.invokeServiceClass(RPCUtil.java:190)
    at org.apache.axis2.rpc.receivers.RPCMessageReceiver.invokeBusinessLogic(RPCMessageReceiver.java:117)
    at org.apache.axis2.receivers.AbstractInOutMessageReceiver.invokeBusinessLogic(AbstractInOutMessageReceiver.java:40)
    at org.apache.axis2.receivers.AbstractMessageReceiver.receive(AbstractMessageReceiver.java:114)
    at org.apache.axis2.engine.AxisEngine.receive(AxisEngine.java:181)
    at org.apache.axis2.transport.http.HTTPTransportUtils.processHTTPPostRequest(HTTPTransportUtils.java:172)
    at org.apache.axis2.transport.http.AxisServlet.doPost(AxisServlet.java:146)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:727)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
    at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
    at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
    at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
    at java.lang.Thread.run(Unknown Source)

是的之后跟踪 LogCat 我没有检查 tomcat 服务器日志，如果 SoapUi 成功测试了该服务，您应该监控每次更改测试中的所有日志，我什至一开始忘记启动数据库服务，所以要小心:)

Soap Call

public SoapObject SoapCall(Vector<PropertyInfo> propertyInfo)

    {       

         Integer parametersSize = propertyInfo.size();

         //Initialize soap request + add parameters
         SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

         for(int i=0;i<parametersSize;i++)
         {
             request.addProperty(propertyInfo.get(i));
         }


        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        //envelope.dotNet = false; if service of type asmx .NET
        envelope.setOutputSoapObject(request);

        Log.d("App Log c ","c");

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
        try {
            System.out.println(androidHttpTransport.getPort());
            // Make the soap call.
            //this is the actual part that will call the webservice
             androidHttpTransport.call(SOAP_ACTION, envelope);                      

             SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
             //Log.i("App Log 1 ", response.toString());

        } catch (Exception e) {
            e.printStackTrace(); 
        }

        // Get the SoapResult from the envelope body.       
        SoapObject result = (SoapObject)envelope.bodyIn;
        Log.i("App Log 2 ", result.toString());
        Log.i("App Log 2 ", result.getProperty(0).toString());

        return result;

    }

 Vector<PropertyInfo> vectorProperyInfo = new Vector<PropertyInfo>();

            PropertyInfo userProp = new PropertyInfo();
            userProp.setName("userName");
            userProp.setValue(username);
            userProp.setType(String.class);
            vectorProperyInfo.addElement(userProp);

            PropertyInfo passProp = new PropertyInfo();
            passProp.setName("pass");
            passProp.setValue(password);
            passProp.setType(String.class);
            vectorProperyInfo.addElement(passProp);

            SoapObject result = soapUtil.SoapCall(vectorProperyInfo);

           if (result != null && result.getProperty(0).toString().equals("1")) {
            return "LOGIN_SUCCESS";// for a student
        }

PS 我的数据库是 Oracle并且webservice是soap并使用 axis2-1.2 bin 并且在 Android 4.0 上测试，上述错误响应代码为 500 内部错误