iOS 划分时出现 INFINITY 问题
我在 iPhon 应用程序中遇到无穷大问题。问题很奇怪。我需要使用以下公式计算缩放限制。
zoomLimit = 1/(mapState.iBufferMult*0.75);
mapState.iBufferMult 的值 = 3
问题是大多数类型的公式给出的正确值是 0.44。但有时它会给出无限。
谁能告诉我为什么会这样。
I am getting infinity problem in an iPhon application. The problem is very strange. I need to calculate the zoom limit using the following formula.
zoomLimit = 1/(mapState.iBufferMult*0.75);
The value of mapState.iBufferMult = 3
The problem is that most of the type the formula gives the correct value 0.44. But sometimes it gives INFINITY.
Can anyone tell me why it is doing like that.
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因为当表达式为 INFINITY 时，
mapState.iBufferMult为 0。你的程序中的某些东西将其设置为 0。记录它和除法的结果并每次检查。Because
mapState.iBufferMultis 0 in the cases where the expression is INFINITY. Something in your program is setting it to 0. Log it and the result of the division and check every time.因为有时
mapState.iBufferMult==0。检查你没有悬空指针。
because sometimes
mapState.iBufferMult==0.Check you haven't got a dangling pointer.
是的，我可以：当
mapState.iBufferMult为0（零）时：解决
mapState.iBufferMult问题，您就解决了这个问题。Yes, I can: when
mapState.iBufferMultis0(zero) then:Solve the
mapState.iBufferMultproblem and you've solved this one.因为某些有时，
mapState为 nil 或mapState.iBufferMult为 0。或者问题出在该行之外。
也许在那里设置一个断点，并在 ZoomLimit 为 INFINITY 时停止。
Because some of the time,
mapStateis nil ormapState.iBufferMultis 0.Or the problem lies outside of this line.
Maybe set a breakpoint there and halt when zoomLimit is INFINITY.