在 servlet 中使用网站的 API。这是正确的方法吗？

发布于 2024-10-06 08:55:35 字数 144 浏览 1 评论 0原文

public java.lang.StringBuffer getRequestURL()

我正在使用此方法调用另一个网站的 API，该网站提供 XML 数据作为对其的响应。这是用于 HTTP 请求/响应的正确方法吗？？

原文

public java.lang.StringBuffer getRequestURL()

I am using this method to call the API of another website which gives XML data as response to it . Is this the right method to be used with HTTPrequest/response. ?

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凌乱心跳 2024-10-13 08:55:35

不。您应该使用 new URL(url).openConnection() 或一些抽象，例如 http 组件或 rest-client

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倾听心声的旋律 2024-10-13 08:55:35

如果您想从 Servlet 中发出 HTTP 请求，您可以像从任何进程中那样进行操作。类似这样：

public static void main(String[] args) throws Exception {

  URL url = new URL("http://www.targetdomain.com/api?key1=value1&key2=value2...");

  HttpURLConnection conn = (HttpURLConnection) url.openConnection();
  conn.setConnectTimeout(5000);    // 5 seconds
  conn.setRequestMethod("GET");       
  conn.connect();
  BufferedReader rd  = new BufferedReader(new InputStreamReader(conn.getInputStream()));

  String line;
  StringBuffer bf = new StringBuffer();
  while ((line = rd.readLine()) != null) {
      bf.append(line);
  }
  conn.disconnect(); 

  //... pass bf to an XML parser and do your processing...
}

根据您使用的 XML 解析器，您可能可以跳过缓冲响应并将其放入 StringBuffer 中，而是直接将响应 InputStream 传递给解析器。

If you want to make HTTP requests from within a Servlet you do it as you would from any process. Something like this:

public static void main(String[] args) throws Exception {

  URL url = new URL("http://www.targetdomain.com/api?key1=value1&key2=value2...");

  HttpURLConnection conn = (HttpURLConnection) url.openConnection();
  conn.setConnectTimeout(5000);    // 5 seconds
  conn.setRequestMethod("GET");       
  conn.connect();
  BufferedReader rd  = new BufferedReader(new InputStreamReader(conn.getInputStream()));

  String line;
  StringBuffer bf = new StringBuffer();
  while ((line = rd.readLine()) != null) {
      bf.append(line);
  }
  conn.disconnect(); 

  //... pass bf to an XML parser and do your processing...
}

Depending on whatever XML parser you're using, you can probably skip buffering the response and putting it in a StringBuffer, and instead pass your parser the response InputStream directly.

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