char* 的 printf 出现分段错误
我正在尝试从套接字读取并使用 printf 打印到标准输出（必须）；
然而，每次我从正常的网站读取特定文件（HTML）时，我都会遇到分段错误。
请看一下这段代码并告诉我哪里出了问题。
int total_read = 0;
char* read_buff = malloc(BUF_SIZE);
char* response_data = NULL;
if (read_buff == NULL){
perror("malloc");
exit(1);
}
while((nbytes = read(fd, read_buff, BUF_SIZE)) > 0){
int former_total = total_read;
total_read += nbytes;
response_data = realloc(response_data, total_read);
memmove(response_data + former_total, read_buff, nbytes); //start writing at the end of spot before the increase.
}
if (nbytes < 0){
perror("read");
exit(1);
}
printf(response_data);
谢谢。
I'm Trying to read from a socket and print to stdout using printf (a must);
However I get a Segmentation Fault every time I read a specific file (an HTML) from the sane web site.
Please, take a look at this code and tell me what wrong.
int total_read = 0;
char* read_buff = malloc(BUF_SIZE);
char* response_data = NULL;
if (read_buff == NULL){
perror("malloc");
exit(1);
}
while((nbytes = read(fd, read_buff, BUF_SIZE)) > 0){
int former_total = total_read;
total_read += nbytes;
response_data = realloc(response_data, total_read);
memmove(response_data + former_total, read_buff, nbytes); //start writing at the end of spot before the increase.
}
if (nbytes < 0){
perror("read");
exit(1);
}
printf(response_data);
Thank You.
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评论（3）
response_data可能不是 NUL ('\0') 终止，因此printf会继续到字符串末尾。或者它可能包含%指令，但printf无法找到更多参数。相反，告诉
printf读取多远，并且不解释字符串中的任何%指令。请注意，如果
response_data包含嵌入的 NUL，即使total_read更长，printf也会在那里停止。response_datais probably not NUL ('\0') terminated, soprintfcontinues past the end of the string. Or possibly it contains a%directive butprintfcan't find further arguments.Instead, tell
printfhow far to read, and not to interpret any%directives in the string.Note that if
response_datacontains an embedded NUL,printfwill stop there even iftotal_readis longer.response_data中可能包含什么？如果它包含 printf 格式字符（即%后跟常用选项之一），printf将尝试访问一些您未传递的参数，并出现分段错误很有可能。尝试使用puts来代替？如果必须使用 printf，请执行
printf("%s", response_data)（并首先以 NUL 终止）What's likely to be in
response_data? If it contains printf-formatting characters (i.e.%followed by one of the usual options),printfwill try to access some parameters you've not passed, and a segmentation fault is quite likely. Tryputsinstead?If you must use printf, do
printf("%s", response_data)(and NUL-terminate it first)我从您的帖子中了解到，响应是 HTML 数据。
由于它是文本，因此您尝试打印它。不要像您那样使用 printf。
相反，请执行以下操作：
My understanding from your post is that the response is the HTML data.
And since it is text you attempt to print it. Do not use printf the way you do.
Instead do the following: