通过“这个”初始化列表的对象
我已将问题简化为以下示例代码：
class Charizard { //truck
trainer &myTrainer;
public:
Charizard(trainer &tMyTrainer);
};
class trainer {
Charizard myPokemon;
public:
trainer();
};
Charizard::Charizard(trainer &tMyTrainer) : myTrainer(tMyTrainer) {}
在不更改或添加公共成员的情况下，如何为训练器创建构造函数，以便在初始化列表中创建 myPokemon 时，“myTrainer”指向正在运行的训练器创建？
这是我尝试过的：
trainer::trainer() : myPokemon(this) {}
但当然“this”不是正确的类型。我无法更改 Charizard 构造函数所接受的内容（它是公共成员），所以我不知道该怎么做。有什么想法吗？
注意：标题可能需要一些修改。
I've reduced the problem down to the following sample code:
class Charizard { //truck
trainer &myTrainer;
public:
Charizard(trainer &tMyTrainer);
};
class trainer {
Charizard myPokemon;
public:
trainer();
};
Charizard::Charizard(trainer &tMyTrainer) : myTrainer(tMyTrainer) {}
Without changing or adding public members, how can I create the constructor for trainer, such that when myPokemon is created in the initialization list, the "myTrainer" points back to the trainer being created?
Here is what I tried:
trainer::trainer() : myPokemon(this) {}
But of course "this" is not the correct type. I cannot change what the Charizard constructor takes in (it's a public member), so I'm not sure what to do. Any ideas?
Note: Title might need some work.
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如果您需要实例对象而不是指针，请尝试：
如果
Charizard尝试在其构造函数中调用tMyTrainer上的任何方法，请小心，因为您的新trainer< /code> 对象当时尚未完全构建。If you need an instance object instead of a pointer, try:
Be careful if
Charizardtries to call any methods ontMyTrainerin its constructor, because your newtrainerobject has not yet been fully constructed at that time.需要引用类型 - 只需使用
*this而不是this。无论如何，许多编译器都会对此发出警告：
myPokemon将在trainer完成之前构建，因此它会获得对非构造的trainer的引用>。小心不要调用它的任何方法（或使用它的数据），因为它会导致未定义的行为！A reference type is expected - just use
*thisinstead ofthis.A lot of compilers will warn about this anyway:
myPokemonwill be constructed beforetraineris done, so it gets a reference to a non-constructedtrainer. Be careful not to call any methods on it (or use its data) since it leads to undefined behavior!