如何使用 Python 从 YouTube 链接中提取视频 ID？

Question

我知道使用 PHP 的 parse_url 和 parse_str 函数可以轻松完成此操作：

$subject = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1";
$url = parse_url($subject);
parse_str($url['query'], $query);
var_dump($query);

但是如何使用 Python 实现此目的？我可以执行urlparse，但是接下来怎么办？

Answer 1

Python 有一个用于解析 URL 的库。

import urlparse
url_data = urlparse.urlparse("http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1")
query = urlparse.parse_qs(url_data.query)
video = query["v"][0]

Answer 2

这是 Mikhail Kashkin 解决方案的 Python3 版本，添加了场景。

from urllib.parse import urlparse, parse_qs
from contextlib import suppress


# noinspection PyTypeChecker
def get_yt_id(url, ignore_playlist=False):
    # Examples:
    # - http://youtu.be/SA2iWivDJiE
    # - http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu
    # - http://www.youtube.com/embed/SA2iWivDJiE
    # - http://www.youtube.com/v/SA2iWivDJiE?version=3&hl=en_US
    query = urlparse(url)
    if query.hostname == 'youtu.be': return query.path[1:]
    if query.hostname in {'www.youtube.com', 'youtube.com', 'music.youtube.com'}:
        if not ignore_playlist:
        # use case: get playlist id not current video in playlist
            with suppress(KeyError):
                return parse_qs(query.query)['list'][0]
        if query.path == '/watch': return parse_qs(query.query)['v'][0]
        if query.path[:7] == '/watch/': return query.path.split('/')[2]
        if query.path[:7] == '/embed/': return query.path.split('/')[2]
        if query.path[:3] == '/v/': return query.path.split('/')[2]
   # returns None for invalid YouTube url

# unit test
@pytest.mark.parametrize(
    'url,expected_id',
    (
        ('https://youtu.be/Dlxu28sQfkE', 'Dlxu28sQfkE'),
        ('https://www.youtube.com/watch?v=Dlxu28sQfkE&feature=youtu.be', 'Dlxu28sQfkE'),
        ('https://www.youtube.com/watch/Dlxu28sQfkE', 'Dlxu28sQfkE'),
        ('https://www.youtube.com/embed/Dlxu28sQfkE', 'Dlxu28sQfkE'),
        ('https://www.youtube.com/v/Dlxu28sQfkE', 'Dlxu28sQfkE'),
        ('https://www.youtube.com/playlist?list=PLRbcUrcJVEmX_eaAsubNOWfE4SlhGqjW4', 'PLRbcUrcJVEmX_eaAsubNOWfE4SlhGqjW4'),
    ),
)
def test_yt_id(url, expected_id):
    assert get_yt_id(url) == expected_id

Answer 3

这是正则表达式，它涵盖了这些情况

((?<=(v|V)/ )|(?<=be/)|(?<=(\?|\&)v=)|(?<=嵌入/))([\w-]+)

Answer 4

我使用这个很棒的包 pytube。$ pip install pytube< /code>

#Examples
url1='http://youtu.be/SA2iWivDJiE'
url2='http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu'
url3='http://www.youtube.com/embed/SA2iWivDJiE'
url4='http://www.youtube.com/v/SA2iWivDJiE?version=3&hl=en_US'
url5='https://www.youtube.com/watch?v=rTHlyTphWP0&index=6&list=PLjeDyYvG6-40qawYNR4juzvSOg-ezZ2a6'
url6='youtube.com/watch?v=_lOT2p_FCvA'
url7='youtu.be/watch?v=_lOT2p_FCvA'
url8='https://www.youtube.com/watch?time_continue=9&v=n0g-Y0oo5Qs&feature=emb_logo'

urls=[url1,url2,url3,url4,url5,url6,url7,url8]

#Get youtube id
from pytube import extract
for url in urls:
    id=extract.video_id(url)
    print(id)

输出

SA2iWivDJiE
_oPAwA_Udwc
SA2iWivDJiE
SA2iWivDJiE
rTHlyTphWP0
_lOT2p_FCvA
_lOT2p_FCvA
n0g-Y0oo5Qs

Answer 5

match = re.search(r"youtube\.com/.*v=([^&]*)", "http://www.youtube.com/watch?v=z_AbfPXTKms&test=123")
if match:
    result = match.group(1)
else:
    result = ""

未经测试。

Answer 6

您可以使用

from urllib.parse import urlparse

url_data = urlparse("https://www.youtube.com/watch?v=RG9TMn1FJzc")
print(url_data.query[2::])

Answer 7

当这些参数可以按任何顺序出现时，拆分字符串是一个非常糟糕的主意。坚持使用 urlparse：

from urllib.parse import parse_qs, urlparse

def video_id(url):
    """
    Get youtube video ID from url
    ID is last element of url path for youtu.be and shorts
    """
    id = None
    parse = urlparse(url)
    if parse.netloc.lower() == 'youtu.be' or parse.path.lower().startswith('/shorts'):
        id = parse.path.split('/')[-1:]
    elif parse.query:
        id = parse_qs(parse.query).get('v')
    return id[0] if id else ''

Answer 8

您可以尝试使用正则表达式作为 YouTube 视频 ID：

# regex for the YouTube ID: "^[^v]+v=(.{11}).*"
result = re.match('^[^v]+v=(.{11}).*', url)
print result.group(1)

Answer 9

不需要正则表达式。在 ? 上拆分，取第二个，在 = 上拆分，取第二个，在 & 上拆分，取第一个。

Answer 10

虽然这需要搜索查询，但会为您提供 id：

from youtube_search import YoutubeSearch    
results = YoutubeSearch('search terms', max_results=10).to_json()    
print(results)

Answer 11

url = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1"
parsed = url.split("?")
videoId = parsed[1]
print(videoId)

这适用于所有类型的 YouTube 视频链接。

Answer 12

我很晚了，但我使用这个片段来获取视频 ID。

def video_id(url: str) -> str:
    """Extract the ``video_id`` from a YouTube url.
    This function supports the following patterns:
    - :samp:`https://youtube.com/watch?v={video_id}`
    - :samp:`https://youtube.com/embed/{video_id}`
    - :samp:`https://youtu.be/{video_id}`
    :param str url:
        A YouTube url containing a video id.
    :rtype: str
    :returns:
        YouTube video id.
    """
    return regex_search(r"(?:v=|\/)([0-9A-Za-z_-]{11}).*", url, group=1)

def regex_search(pattern: str, string: str, group: int):
    """Shortcut method to search a string for a given pattern.
    :param str pattern:
        A regular expression pattern.
    :param str string:
        A target string to search.
    :param int group:
        Index of group to return.
    :rtype:
        str or tuple
    :returns:
        Substring pattern matches.
    """
    regex = re.compile(pattern)
    results = regex.search(string)
    if not results:
        return False

    return results.group(group)

Answer 13

我用这个

def getId(videourl):
    vidid=videourl.find('watch?v=')
    Id = videourl[vidid+8:vidid+19]
    if vidid==-1:
        vidid=videourl.find('be/')
        Id=videourl[vidid+3:]
    return Id

Answer 14

我创建了没有正则表达式的 youtube id 解析器：

import urlparse

def video_id(value):
    """
    Examples:
    - http://youtu.be/SA2iWivDJiE
    - http://www.youtube.com/watch?v=_oPAwA_Udwc&feature=feedu
    - http://www.youtube.com/embed/SA2iWivDJiE
    - http://www.youtube.com/v/SA2iWivDJiE?version=3&hl=en_US
    """
    query = urlparse.urlparse(value)
    if query.hostname == 'youtu.be':
        return query.path[1:]
    if query.hostname in ('www.youtube.com', 'youtube.com'):
        if query.path == '/watch':
            p = urlparse.parse_qs(query.query)
            return p['v'][0]
        if query.path[:7] == '/embed/':
            return query.path.split('/')[2]
        if query.path[:3] == '/v/':
            return query.path.split('/')[2]
    # fail?
    return None