PHP 嵌套引号
以下失败：
$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$_SESSION['userID']'");
我尝试了以下操作：
$userID = $_SESSION['userID'];
$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$userID'");
并且它有效。有没有办法在不创建单独变量的情况下做到这一点？
谢谢！
The following fails:
$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$_SESSION['userID']'");
I tried the following:
$userID = $_SESSION['userID'];
$result = mysql_query("SELECT * FROM Tasks WHERE UserID = '$userID'");
and it works. Is there a way to do this without making a separate variable?
Thanks!
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或者像这样：
Or like this:
或者
值得注意的是，它会推荐第一个，因为当您使用 php 编辑器时，它会更容易阅读/查找，这反过来又使调试更容易
or
worth noting it would recommend the first one because it gets easier to read/find when you use a php editor, which in return makes it easier to debugg
您的第一个查询会阻塞，因为您实际上是在命令 WHERE
userIDis'$_SESSION['。更不用说其余的userID']}'将被 MySQL 解释为语法错误。Your first chokes the query, because you're actually commanding WHERE
userIDis'$_SESSION['. Not to mentions that rest which isuserID']}'will be interpreted as a syntax error by MySQL.是的，像这样
Yes, like this