如何在 Windows Shell 中迭代一组文件夹？
我目前正在尝试编写一个 .cmd Windows Shell 脚本来迭代一组文件夹。然而，即使是下面最简单的脚本：
echo "%ROOT%"
for %%f in ("%ROOT%\Binaries\" ) do (
echo "%%f"
if not exist "%%f\Subfolder"
md "%%f\Subfolder"
)
输出：
CurrentDir>echo "<ActualPathToRoot>"
"<ActualPathToRoot>"
%f\Subfolder was unexpected at this time
CurrentDir>if exists "%f\Subfolder"
我做错了什么？如何更改该脚本，以便它迭代该一个文件夹，并且一旦发现没有名为“Subfolder”的子文件夹，它就会创建该子文件夹？还有关于编写此类脚本的好教程吗？
I'm currently trying to write a .cmd Windows Shell script that would iterate over a set of folders. However even the following simplest script:
echo "%ROOT%"
for %%f in ("%ROOT%\Binaries\" ) do (
echo "%%f"
if not exist "%%f\Subfolder"
md "%%f\Subfolder"
)
outputs:
CurrentDir>echo "<ActualPathToRoot>"
"<ActualPathToRoot>"
%f\Subfolder was unexpected at this time
CurrentDir>if exists "%f\Subfolder"
What am I doing wrong? How do I alter that script so that it iterates over that one folder and once it see there's no subfolder named "Subfolder" it creates that subfolder? Also is there a good tutorial on writing such scripts?
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对于（子）文件夹迭代，您需要使用不同的
for参数。因此，如果您想列出 C: 的所有目录，您应该这样做：
注意指示目录的参数
/d。要进入子目录，您需要使用/r进行递归，这将遍历所有 Windows 子目录查找 JPG。瞧你应该能够做到
/d /r并且此参考建议你可以 -我根本做不到，但也许你能做到这一点？我快速记下的一个解决方法是在 for 循环中对所有目录执行
dir：请注意，
dir与/ad/s/ 结合使用b执行目录的递归列表，打印找到的目录的名称。有了这些工具，您应该能够构建 if 子文件夹。请注意，您可能需要
For (sub)folder-iteration you need to use a different
forparameter.So if you want to list all directories of C: you should do this:
Note the parameter
/dwhich indicates a directory. To go into subdirectories you need to do a recursive for with/rThis would iterate through all Windows subdirectories looking for JPGs. Low behold you should be able to do
/d /rand this reference suggests you can - I simply can't, but maybe you are able to do this?A workaround I quickly jotted down is to just do a
dirof all directories in a for loop:Note that
diris used in conjunction with/ad/s/bwhich performs a recursive listing of directories, printing the names of the directories found.With these tools in your hand you should be able to do your if-subfolder construct. Note that you might need
这对我有用：
This works for me: