读取缓冲的二进制文件（带查找）
假设我需要读取巨大的整数二进制文件，一个方便的方法是：
FileInputStream fi = new FileInputStream(file);
BufferedInputStream bi = new BufferedInputStream( fi);
DataInputStream di =new DataInputStream(bi);
但现在假设我必须读取从第 n 个整数开始的巨大块。 到目前为止，我已经自己实现了一种缓冲区：
RandomAccessFile fp=new RandomAccessFile(file);
fp.seek(position);
byte[] buff= new byte[len];
fp.read(buff, 0, len);
ByteArrayInputStream bIn = new ByteArrayInputStream(buff);
DataInputStream dIn= new DataInputStream(bIn);
现在我可以解析 buff 中的数据，处理它，然后读取下一个块。
我想知道是否有一些我可以使用的标准缓冲区对象。我想简化我的代码，而不是自己处理缓冲。
欢迎任何提示。 雅各布
Say I need to read huge binary file of integers, a handy way is:
FileInputStream fi = new FileInputStream(file);
BufferedInputStream bi = new BufferedInputStream( fi);
DataInputStream di =new DataInputStream(bi);
But now say I have to read a huge block starting from the n-th integer.
So far I have implemented a sort of buffer by myself as:
RandomAccessFile fp=new RandomAccessFile(file);
fp.seek(position);
byte[] buff= new byte[len];
fp.read(buff, 0, len);
ByteArrayInputStream bIn = new ByteArrayInputStream(buff);
DataInputStream dIn= new DataInputStream(bIn);
now I can parse the data in buff, process it and then read the next block.
I was wondering if there was some standard buffer object I could have used. I would like to simplify my code and not to take care of the buffering by myself.
Any hint is welcome.
Jacopo
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看看蔚来。例如，java.nio.MappedByteBuffer。
Have a look at NIO. For example, java.nio.MappedByteBuffer.
只需从 fi.skip(position) 开始，然后用 bi 和 di 包装它。当position足够大时，底层流实际上会调用seek。
Just start with fi.skip(position) before wrapping it with bi and di. The underlying stream actually makes a call to seek when position is sufficiently large.