从图库短代码中排除 the_post_thumbnail

Question

我使用此代码在页面上创建一个简单的图库：

<?php echo do_shortcode('[gallery itemtag="ul" icontag="li" size="full" columns="0" link="file" ]'); ?>

现在的问题是最终用户必须通过媒体页面上传图像，然后才能选择该图像作为特色图像。

我知道可以通过将特色图像的 ID 添加到短代码的排除列表中来解决这个问题，但如何自动获取此 ID？

Answer 1

function exclude_thumbnail_from_gallery($null, $attr)
{
    if (!$thumbnail_ID = get_post_thumbnail_id())
        return $null; // no point carrying on if no thumbnail ID

    // temporarily remove the filter, otherwise endless loop!
    remove_filter('post_gallery', 'exclude_thumbnail_from_gallery');

    // pop in our excluded thumbnail
    if (!isset($attr['exclude']) || empty($attr['exclude']))
        $attr['exclude'] = array($thumbnail_ID);
    elseif (is_array($attr['exclude']))
        $attr['exclude'][] = $thumbnail_ID;

    // now manually invoke the shortcode handler
    $gallery = gallery_shortcode($attr);

    // add the filter back
    add_filter('post_gallery', 'exclude_thumbnail_from_gallery', 10, 2);

    // return output to the calling instance of gallery_shortcode()
    return $gallery;
}
add_filter('post_gallery', 'exclude_thumbnail_from_gallery', 10, 2);

Answer 2

<?php  $id = get_post_thumbnail_id(get_the_ID()); // gets the post thumbnail ID ?>
<?php echo do_shortcode('[gallery exclude='.$id.' link="file" itemtag="div" icontag="span" captiontag="p" size="thumbnail" columns="4" ]'); ?> 

Answer 3

怎么样？

echo do_shortcode('[gallery exclude="' . get_post_thumbnail_id( $post->ID ) . '"]');