NSDictionary objectForKey/valueForKey 已格式化？

发布于 2024-10-06 00:59:40 字数 503 浏览 8 评论 0原文

我正在接收 JSON 数据并将其转换为字典。打印字典结果如下：

Objekt: {
author = blub;
authorUID = 28084;
date = "31.07.10";
numVotes = 0;
postUID = 30931;
text = "... <b>Atemtest</b> durchf\U00c3\U00bchren m\U00c3\U00bcssen?...";
timestamp = 1280585555;}

我想要的是将出现的 \U00c3\U00bc 替换为 \U00bc。

这就是我被困住的地方。 [dictionary objectForKey:@"text"] 返回一个已经格式化的字符串，如 Atemtest durchführen zu müssen?

valueForKey 的行为相同。

原文

I am receiving JSON-Data and convert it into a Dictionary.
Printing the Dictionary results in the Following description:

Objekt: {
author = blub;
authorUID = 28084;
date = "31.07.10";
numVotes = 0;
postUID = 30931;
text = "... <b>Atemtest</b> durchf\U00c3\U00bchren m\U00c3\U00bcssen?...";
timestamp = 1280585555;}

What I want is to replace the occurences of e.g. \U00c3\U00bc with \U00bc.

That's where I'm stuck. [dictionary objectForKey:@"text"] returns an already formatted String like <b>Atemtest</b> durchfÃ¼hren zu mÃ¼ssen?

valueForKey behaves the same.

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过期以后 2024-10-13 00:59:40

两个输出只是字典中同一底层 NSString 对象的不同表示，我相信它已经从 JSON 中的任何内容重新编码为 UTF-16。

正如 Peter Hosey 对此相关问题的回答所述，NSDictionary 的输出正在对字符串进行编码，使其符合 plist 的预期文本表示形式。

在你的情况下，听起来你可能真的不想回到那个表示（尽管如果你这样做，那么看看上述问题的接受答案），而是直接在 NSString 中进行替换，像这样：

NSString* oldStr = @"\u00c3\u00bc";
NSString* newStr = @"\u00bc";

NSString* text = [dictionary objectForKey:@"text"];
NSString* replaced = [text stringByReplacingOccurrencesOfString:oldStr withString:newStr];

源代码中的\uXXXX序列将被转换为NSString常量中的相关UTF-16字符，然后这些将在目标。

Both outputs are just different representations of the same underlying NSString object in the dictionary, which I believe is already recoded as UTF-16 from whatever it was in the JSON.

As described by Peter Hosey's answer to this related question, the output from NSDictionary is encoding the string so that it conforms to the expected textual representation of a plist.

In your case, it sounds like you probably don't really want to go back to that representation (although if you do then have a look at the accepted answer to the aforementioned question), but instead do the substitution directly in the NSString, something like this:

NSString* oldStr = @"\u00c3\u00bc";
NSString* newStr = @"\u00bc";

NSString* text = [dictionary objectForKey:@"text"];
NSString* replaced = [text stringByReplacingOccurrencesOfString:oldStr withString:newStr];

The \uXXXX sequences in the source code will be converted into the relevant UTF-16 characters in the NSString constants, and these will then be matched and substituted in the target.

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