将 BeginInvoke 作为参数传递
假设我想要一个传递对象的 BeginInvoke 方法的方法作为参数。我该怎么做呢？该调用如下所示：
MyRandomMethod(SomeControl.BeginInvoke);
MyRandomMethod 的方法定义是什么？
部分问题在于 BeginInvoke 具有重载，因此编译器会混淆我尝试将哪一个作为参数传递。也许我需要找到一种方法来说明我指的是哪个版本的 BeginInvoke？ （虽然我想这将由参数类型决定）
Suppose I want to have a method that passes the BeginInvoke method of an object as a parameter. How would I do that? The call looks like this:
MyRandomMethod(SomeControl.BeginInvoke);
What would the method definition for MyRandomMethod be?
Part of the problem is that BeginInvoke has overloads, so the compiler gets confused as to which one I am try to pass as a parameter. Maybe I need to find a way to say which version of BeginInvoke I am referring to? (Though I would imagine that would be decided by the parameter type)
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评论（1）
MyRandomMethod必须有一个带有委托的参数，该委托与SomeControl.BeginInvoke的重载之一匹配。例如：或
（但请不要使用这两个签名重载
MyRandomMethod本身，否则您只是在自找混乱。）MyRandomMethodwould have to have a parameter with a delegate which matches one of the overloads forSomeControl.BeginInvoke. For example:or
(But please don't overload
MyRandomMethoditself with both of these signatures, as otherwise you're just asking for confusion.)