需要 JavaScript 帮助（YQL 和 JavaScript）

发布于 2024-10-05 20:31:19 字数 1107 浏览 4 评论 0原文

我有这个“改编”的JavaScript代码来显示任何事情的有趣事实（在本例中是关于电影和/或历史）然而，它一次只显示一个事实，用户需要按一个按钮才能显示另一个事实。

我的问题是，有没有一种方法可以一次显示所有事实，而不是一次只显示一个事实？

function funfacts(o){
  var facts = document.getElementById('funfacts');
  facts.className = 'js';
  if(facts){
    var data = o.query.results.p;
    var link = facts.getElementsByTagName('a')[0];
    link.innerHTML = '(see all facts)';
    var out = document.createElement('p');
    out.className = 'fact';
    facts.insertBefore(out,link.parentNode);
    function seed(){
      var ran = parseInt(Math.random()*data.length);
      out.innerHTML = data[ran];
    }
    var b = document.createElement('button');
    b.innerHTML = 'get another fact';
    b.onclick = seed;
    link.parentNode.insertBefore(b,link);
    seed();
  }
}

  <script src="http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D'http%3A%2F%2Fwww.tealdragon.net%2Fhumor%2Ffacts%2Ffacts.htm'%20and%20xpath%3D'%2F%2Fli%2Fp'&format=json&diagnostics=true&callback=funfacts"></script>

原文

I have this "adapted" javascript code to display funfacts about anything (in this case about movies and/or History)
However, it is built to display only one fact at a time, the user needs to press a button to display another funfact.

My question is, is there a way to display all the facts at once and not just one at a time?

function funfacts(o){
  var facts = document.getElementById('funfacts');
  facts.className = 'js';
  if(facts){
    var data = o.query.results.p;
    var link = facts.getElementsByTagName('a')[0];
    link.innerHTML = '(see all facts)';
    var out = document.createElement('p');
    out.className = 'fact';
    facts.insertBefore(out,link.parentNode);
    function seed(){
      var ran = parseInt(Math.random()*data.length);
      out.innerHTML = data[ran];
    }
    var b = document.createElement('button');
    b.innerHTML = 'get another fact';
    b.onclick = seed;
    link.parentNode.insertBefore(b,link);
    seed();
  }
}

  <script src="http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D'http%3A%2F%2Fwww.tealdragon.net%2Fhumor%2Ffacts%2Ffacts.htm'%20and%20xpath%3D'%2F%2Fli%2Fp'&format=json&diagnostics=true&callback=funfacts"></script>

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羁客 2024-10-12 20:31:19

变量data包含数组中的所有事实。当用户单击时，函数 seed 会从数组中随机选择一项。

因此，要显示全部内容：

out.innerHTML = data.join("<br />");

这会将事实连接到单个字符串中，并用换行符分隔。

编辑添加：

这是一个完整、非常简单的网页示例，显示所有项目：

<html>
<body>
<div id="funfacts">
</div>
<script>
function funfacts(o){
  var facts = document.getElementById('funfacts');
  if(facts){
    var data = o.query.results.p;
    var out = document.createElement('p');
    out.className = 'fact';
    facts.appendChild(out);
    out.innerHTML = data.join("<br />");
  }
}
</script>
<script src="http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D'http%3A%2F%2Fwww.tealdragon.net%2Fhumor%2Ffacts%2Ffacts.htm'%20and%20xpath%3D'%2F%2Fli%2Fp'&format=json&diagnostics=true&callback=funfacts"></script>

</body>
</html>

The variable data contains all of the facts in an array. When the user clicks, the function seed is randomly selecting one item out of the array.

So, to display them all:

out.innerHTML = data.join("<br />");

This joins the facts into a single string, separated by newlines.

Edited to add:

Here's an example of a complete, very simple web page that displays all of the items:

<html>
<body>
<div id="funfacts">
</div>
<script>
function funfacts(o){
  var facts = document.getElementById('funfacts');
  if(facts){
    var data = o.query.results.p;
    var out = document.createElement('p');
    out.className = 'fact';
    facts.appendChild(out);
    out.innerHTML = data.join("<br />");
  }
}
</script>
<script src="http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20html%20where%20url%3D'http%3A%2F%2Fwww.tealdragon.net%2Fhumor%2Ffacts%2Ffacts.htm'%20and%20xpath%3D'%2F%2Fli%2Fp'&format=json&diagnostics=true&callback=funfacts"></script>

</body>
</html>

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