如何通过 mocha 和 test/unit 正确存根 Rails 关联方法？
我正在开发一个应用程序，其中大多数（如果不是全部）数据的范围都在 current_organization 范围内。因此，在我的控制器中的查找调用中，我有类似这样的事情：
def show
@user = current_organization.users.find(params[:id])
end
但是，在我的控制器测试中，我很难找出正确的方法（或任何方法）来存根这些调用，以便我可以测试例如：
get :show, :id => 1
assert_response :success
那些失败的说法是“AR 无法找到 ID = 1 且organization_id = 3 的用户”或其他内容。无论我如何尝试，我似乎都无法回避它。
我的设置块看起来像这样：
setup do
company = organizations(:company) # fixture
@controller.stubs(:current_organization).returns(company)
# now what do I stub, if anything?
end
我尝试做类似的事情： company.stubs(:users).returns([users(:one), users(:two)]) 但事实并非如此之所以有效，是因为基本数组不存在 AR find() 调用。
我是否应该将 fake users 数组设置为像 fake_users 这样的变量，然后执行类似 fake_users.stubs(:find).returns(@user) 的操作？感觉不对，但也许这才是正确的方法。
我只是在寻找处理这个问题的最佳方法。我正在使用摩卡和测试/单元，如果这很重要或有帮助的话。
谢谢！
I'm working on an app where most, if not all, of the data is scoped to a current_organization. So in my find calls in my controllers, I have things like this for example:
def show
@user = current_organization.users.find(params[:id])
end
However, in my controller tests, I'm having a hard time figuring out the proper way (or any way) to stub these calls so that I can test things like:
get :show, :id => 1
assert_response :success
Those are failing saying "AR can't find user with ID=1 and organization_id = 3" or whatever. No matter what I try, I can't seem to get around it.
My setup block looks something like this:
setup do
company = organizations(:company) # fixture
@controller.stubs(:current_organization).returns(company)
# now what do I stub, if anything?
end
I tried doing stuff like: company.stubs(:users).returns([users(:one), users(:two)]) but that doesn't work because the AR find() call doesn't exist for a basic array.
Should I set the fake users array to be a variable like fake_users and then do something like fake_users.stubs(:find).returns(@user)? That didn't feel right, but maybe that's the proper way.
I'm just looking for the best way to handle this. I'm using mocha and test/unit, if that matters or helps.
Thanks!
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评论（1）
除非您特别需要访问
fake_users，否则我认为您可以做的最简单的事情可能是这样的：-不幸的是，这种代码很难模拟。您会注意到我建议的解决方案相当脆弱。
Unless you specifically need access to the
fake_users, I think the simplest thing you could do is probably something like this :-Unfortunately, this kind of code is awkward to mock. You will notice that my suggested solution is rather brittle.