java - 将对象均匀地分布在一条线上

发布于 2024-10-05 16:06:19 字数 690 浏览 2 评论 0原文

我正在由这段代码创建的窗口中的一行上创建对象：

void createTurtles() {
     int nrTurtles = Keyboard.nextInt("Set amount of turtles: ");
     w = new GraphicsWindow(500, 300);
     drawLinez();
     for (int k = 1; k <= nrTurtles; k++) {
        Turtle t = new Turtle(w, 50, 50 + k*10);
        t.right(90);
        t.setSpeed(100);
        t.penDown();
        turtles.add(t);
     }
}

此代码行：

        Turtle t = new Turtle(w, 50, 50 + k*10);

一次创建一只乌龟。现在我已经设置海龟的 Y 坐标为 50，X 坐标为 50+k*10。这是因为该线从 X 坐标 50 开始，到 X 坐标 250 停止。

现在我想要的是，根据创建的海龟数量（用户输入），我希望海龟分布在这条线上均匀。怎么做呢？它与我写的那行有关，可能与 k 值或 10 有关。

该行如图所示（请参见下面的链接），它是红线，即创建海龟的数量。

原文

I am creating objects on a line in a window created by this piece of code:

void createTurtles() {
     int nrTurtles = Keyboard.nextInt("Set amount of turtles: ");
     w = new GraphicsWindow(500, 300);
     drawLinez();
     for (int k = 1; k <= nrTurtles; k++) {
        Turtle t = new Turtle(w, 50, 50 + k*10);
        t.right(90);
        t.setSpeed(100);
        t.penDown();
        turtles.add(t);
     }
}

This codeline:

        Turtle t = new Turtle(w, 50, 50 + k*10);

Creates one turtle at the time. Right now i have set that the turtles will have the Y coordinat of 50, and the X coordinat of 50+k*10. This is because the line starts at the X coordinat of 50 and stops at the X coordinat of 250.

Now what i want is, based on the nr of turtles created (user inputs this), i want the turtles to be spread on this line evenly. How to do it? It has do to with the line that i wrote and maybe the k value or the 10.

The line is illustrated in the picture (see link below), its the red line, that the number of turtles are created at.

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此岸叶落 2024-10-12 16:06:19

将窗口的 height - 100 除以海龟的数量，即可得到 distanceBetweenTurles：

int nrTurtles = Keyboard.nextInt("Set amount of turtles: ");

int height = 300;
w = new GraphicsWindow(500, height);

drawLinez();

double distanceBetweenTurles = (height - 100.0) / nrTurtles;

for (int k = 1; k <= nrTurtles; k++) {
    Turtle t = new Turtle(w, 50, 50 + (int) (k * distanceBetweenTurtles));
    t.right(90);
    t.setSpeed(100);
    t.penDown();
    turtles.add(t);
}

Devide the height - 100 of the window by the number of turtles and you will have your distanceBetweenTurles:

int nrTurtles = Keyboard.nextInt("Set amount of turtles: ");

int height = 300;
w = new GraphicsWindow(500, height);

drawLinez();

double distanceBetweenTurles = (height - 100.0) / nrTurtles;

for (int k = 1; k <= nrTurtles; k++) {
    Turtle t = new Turtle(w, 50, 50 + (int) (k * distanceBetweenTurtles));
    t.right(90);
    t.setSpeed(100);
    t.penDown();
    turtles.add(t);
}

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