自定义to_yaml和domain_type

发布于 2024-10-05 10:21:40 字数 283 浏览 0 评论 0原文

我需要定义用于序列化/反序列化对象的自定义方法。我想做如下的事情。

class Person
  def to_yaml_type
    "!example.com,2010-11-30/Person"
  end

  def to_yaml
    "string representing person"
  end

  def from_yaml(yaml)
    Person.load_from(yaml)
  end
end

声明序列化/反序列化的正确方法是什么？

原文

I need to define custom methods for serializing/deserializing an object. I want to do something like the following.

class Person
  def to_yaml_type
    "!example.com,2010-11-30/Person"
  end

  def to_yaml
    "string representing person"
  end

  def from_yaml(yaml)
    Person.load_from(yaml)
  end
end

What's the correct way to declare the serialization/deserialization?

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空心↖ 2024-10-12 10:21:40

好的，这就是我的想法

class Person

  def to_yaml_type
    "!example.com,2010-11-30/person"
  end

  def to_yaml(opts = {})
    YAML.quick_emit( nil, opts ) { |out|
      out.scalar( taguri, to_string_representation, :plain )
    }
  end

  def to_string_representation
    ...
  end

  def Person.from_string_representation(string_representation)
    ... # returns a Person
  end
end

YAML::add_domain_type("example.com,2010-11-30", "person") do |type, val|
  Person.from_string_representation(val)
end

OK, here's what I came up with

class Person

  def to_yaml_type
    "!example.com,2010-11-30/person"
  end

  def to_yaml(opts = {})
    YAML.quick_emit( nil, opts ) { |out|
      out.scalar( taguri, to_string_representation, :plain )
    }
  end

  def to_string_representation
    ...
  end

  def Person.from_string_representation(string_representation)
    ... # returns a Person
  end
end

YAML::add_domain_type("example.com,2010-11-30", "person") do |type, val|
  Person.from_string_representation(val)
end

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