基于名称的简单 XML 排序

发布于 2024-10-05 07:08:23 字数 750 浏览 4 评论 0原文

我正在尝试按数据库名称对每个数据库中的数据库和文档列表进行排序。然后以表格格式打印它们，

这里是 xml，

<responsedata>
<databases>
<database>
<name>Test</name>
<documents>0</documents>
</database>
−
<database>
<name>Test2</name>
<documents>0</documents>
</database>
</databases>
</responsedata>

这里是我当前的代码，列出了数据库和文档，没有排序，并将它们打印在列表中。

$request_url = "http://255.255.255.255/xmlfile";

$xml = simplexml_load_file($request_url)

foreach ($xml->responsedata->databases->database as $db) {

          echo"<tr><td>",$db->name,"</td><td>",$db->documents,"</td></tr>\n";
  }

原文

I am trying to sort a list of databases and documents in each database by the databasename.
Then print them out in a tabled format

here is the xml

<responsedata>
<databases>
<database>
<name>Test</name>
<documents>0</documents>
</database>
−
<database>
<name>Test2</name>
<documents>0</documents>
</database>
</databases>
</responsedata>

here is my current code that lists the databases and documents without the sort and print them out in a list.

$request_url = "http://255.255.255.255/xmlfile";

$xml = simplexml_load_file($request_url)

foreach ($xml->responsedata->databases->database as $db) {

          echo"<tr><td>",$db->name,"</td><td>",$db->documents,"</td></tr>\n";
  }

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呢古 2024-10-12 07:08:23

$dbs = array();

foreach ($xml->responsedata->databases->database as $db) {
  $dbs[(string)$db->name] = $db;
}

ksort($dbs);

foreach ($dbs as $db) {
  echo"<tr><td>",htmlentities($db->name),"</td>",
      "<td>",htmlentities($db->documents),"</td></tr>\n";
}

$dbs = array();

foreach ($xml->responsedata->databases->database as $db) {
  $dbs[(string)$db->name] = $db;
}

ksort($dbs);

foreach ($dbs as $db) {
  echo"<tr><td>",htmlentities($db->name),"</td>",
      "<td>",htmlentities($db->documents),"</td></tr>\n";
}

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