如何在谷歌应用引擎上使用html5上传多文件(python)
这是我的代码,upload.py:
class MyModel(db.Model):
data = db.BlobProperty(required=True)
mimetype = db.StringProperty(required=True)
class BaseRequestHandler(webapp.RequestHandler):
def render_template(self, filename, template_args=None):
if not template_args:
template_args = {}
path = os.path.join(os.path.dirname(__file__), 'templates', filename)
self.response.out.write(template.render(path, template_args))
class upload(BaseRequestHandler):
def get(self):
self.render_template('index.html',)
def post(self):
file = self.request.POST['file']
obj = MyModel(data=file.value, mimetype=file.type)
obj.put()
o=file
#self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o)))
#return
file_url = "http://%s/download/%d/%s" % (self.request.host, obj.key().id(), file.filename)
self.response.out.write("Your uploaded file is now available at <a href='%s'>%s</a>" % (file_url,file_url,))
和index.html是:
<form enctype="multipart/form-data" action="/" method="post">
<input type="file" name="file" multiple="true" />
<input type="submit" />
</form>
您可以使用 file = self.request.POST['file'] 来获取一个文件,但使用 html5 多文件,
发布时如何使用 python 获取多个文件?
谢谢
上传
现在可以了,请按照这篇文章操作:使用 Google 应用引擎接收多文件帖子
class Download_file(db.Model):
data = db.BlobProperty(required=True)
mimetype = db.StringProperty(required=True)
download_url = db.StringProperty()
class BaseRequestHandler(webapp.RequestHandler):
def render_template(self, filename, template_args=None):
if not template_args:
template_args = {}
path = os.path.join(os.path.dirname(__file__), 'templates', filename)
self.response.out.write(template.render(path, template_args))
class upload(BaseRequestHandler):
def get(self):
files=Download_file.all()
self.render_template('index.html',{'files':files})
def post(self):
files = self.request.POST.multi.__dict__['_items']
#self.response.out.write(files)
for file in files:
file=file[1]
obj = Download_file(data=file.value, mimetype=file.type)
obj.put()
file_url = "http://%s/download/%d/%s" % (self.request.host, obj.key().id(), file.filename)
file_url = "<a href='%s'>%s</a>" % (file_url,file_url,)
obj.download_url=file_url
obj.put()
self.response.out.write("Your uploaded file is now available at %s </br>" % (file_url))
class download(BaseRequestHandler):
def get(self,id,filename):
#id=self.request.get('id')
entity = Download_file.get_by_id(int(id))
self.response.headers['Content-Type'] = entity.mimetype
self.response.out.write(entity.data)
this is my code, the upload.py:
class MyModel(db.Model):
data = db.BlobProperty(required=True)
mimetype = db.StringProperty(required=True)
class BaseRequestHandler(webapp.RequestHandler):
def render_template(self, filename, template_args=None):
if not template_args:
template_args = {}
path = os.path.join(os.path.dirname(__file__), 'templates', filename)
self.response.out.write(template.render(path, template_args))
class upload(BaseRequestHandler):
def get(self):
self.render_template('index.html',)
def post(self):
file = self.request.POST['file']
obj = MyModel(data=file.value, mimetype=file.type)
obj.put()
o=file
#self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o)))
#return
file_url = "http://%s/download/%d/%s" % (self.request.host, obj.key().id(), file.filename)
self.response.out.write("Your uploaded file is now available at <a href='%s'>%s</a>" % (file_url,file_url,))
and the index.html is :
<form enctype="multipart/form-data" action="/" method="post">
<input type="file" name="file" multiple="true" />
<input type="submit" />
</form>
you can use file = self.request.POST['file']
to get one file , but using html5 muti file ,
how to get muti file using python when post ?
thanks
upload
it is ok now , Follow this article: Receive multi file post with google app engine
class Download_file(db.Model):
data = db.BlobProperty(required=True)
mimetype = db.StringProperty(required=True)
download_url = db.StringProperty()
class BaseRequestHandler(webapp.RequestHandler):
def render_template(self, filename, template_args=None):
if not template_args:
template_args = {}
path = os.path.join(os.path.dirname(__file__), 'templates', filename)
self.response.out.write(template.render(path, template_args))
class upload(BaseRequestHandler):
def get(self):
files=Download_file.all()
self.render_template('index.html',{'files':files})
def post(self):
files = self.request.POST.multi.__dict__['_items']
#self.response.out.write(files)
for file in files:
file=file[1]
obj = Download_file(data=file.value, mimetype=file.type)
obj.put()
file_url = "http://%s/download/%d/%s" % (self.request.host, obj.key().id(), file.filename)
file_url = "<a href='%s'>%s</a>" % (file_url,file_url,)
obj.download_url=file_url
obj.put()
self.response.out.write("Your uploaded file is now available at %s </br>" % (file_url))
class download(BaseRequestHandler):
def get(self,id,filename):
#id=self.request.get('id')
entity = Download_file.get_by_id(int(id))
self.response.headers['Content-Type'] = entity.mimetype
self.response.out.write(entity.data)
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您可能想为此使用 blobstore 服务;我写了一系列帖子(1,2,3) 介绍如何使用上传小部件将多个文件上传到 blobstore。
You probably want to use the blobstore service for this; I wrote a series of posts (1, 2, 3) covering how to do multiple-file upload to the blobstore, using an upload widget.
AFAIK,
request.POST['file']
应该是一个文件字典,即POST['file']
应该有键作为上传文件的名称和value 应该分别是文件的内容,即POST['file']['avatar.png'] = ... # raw image data
。我不知道GAE HTTP Request类提供的功能是什么,但应该与此一致。不管怎样,它肯定在
self.request
的某个地方!编辑:
好的,我刚刚注意到 GAE 为您创建了一个文件对象,我的猜测是这应该有效:
AFAIK, the
request.POST['file']
should be a dictionary of files, i.e.POST['file']
should have keys as names of the files uploaded and the value should be the contents of the files respectively, i.e.POST['file']['avatar.png'] = ... # raw image data
.I don't know what's the functionality provided by the GAE HTTP Request class, but it should be consistent to this. Whatever the case, it's definitely in
self.request
, somwhere!EDIT:
Ok, I just noticed GAE creates a file object for you, my guessing is this should work: