抓取GPS位置iPhone SDK

发布于 2024-10-04 20:23:39 字数 2503 浏览 3 评论 0原文

我正在尝试获取iPhone当前位置的位置,但我不确定我做错了什么,没有记录或出现......

代码在这里:

- (void)locationManager:(CLLocationManager *)manager
    didUpdateToLocation:(CLLocation *)newLocation
           fromLocation:(CLLocation *)oldLocation
{
  int degrees = newLocation.coordinate.latitude;
  double decimal = fabs(newLocation.coordinate.latitude - degrees);
  int minutes = decimal * 60;
  double seconds = decimal * 3600 - minutes * 60;
  NSString *lat = [NSString stringWithFormat:@"%d° %d' %1.4f\"", 
           degrees, minutes, seconds];
  statusText.text = lat;
  degrees = newLocation.coordinate.longitude;
  decimal = fabs(newLocation.coordinate.longitude - degrees);
  minutes = decimal * 60;
  seconds = decimal * 3600 - minutes * 60;
  NSString *longt = [NSString stringWithFormat:@"%d° %d' %1.4f\"", 
             degrees, minutes, seconds];
  statusText.text = longt;


}

- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
    double latitude = 0, longitude = 0;
    NSString *esc_addr =  [statusText.text stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
    NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
    if (result) {
        NSScanner *scanner = [NSScanner scannerWithString:result];
        if ([scanner scanUpToString:@"\"lat\":" intoString:nil] && [scanner scanString:@"\"lat\":" intoString:nil]) {
            [scanner scanDouble:&latitude];
            if ([scanner scanUpToString:@"\"lng\":" intoString:nil] && [scanner scanString:@"\"lng\":" intoString:nil]) {
                [scanner scanDouble:&longitude];
            }
        }
    }
    CLLocationCoordinate2D center;
    center.latitude = latitude;
    center.longitude = longitude;
    return center;
}



// Implement viewDidLoad to do additional setup after loading the view, typically from a nib.
- (void)viewDidLoad {
    [super viewDidLoad];
  locationManager = [[CLLocationManager alloc] init];
  locationManager.delegate = self;
  locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move
  locationManager.desiredAccuracy = kCLLocationAccuracyHundredMeters; // 100 m
  [locationManager startUpdatingLocation];

按顺序:获取经度和纬度,使用Google Map API转换它并在应用程序启动时首先调用 locationManager 。

坐标出现只是简单地将它们转换为实际位置并不会发生

I am trying to grab the location of the iPhone's current location and I am not sure what I am doing wrong, nothing logs or appears....

Code is here:

- (void)locationManager:(CLLocationManager *)manager
    didUpdateToLocation:(CLLocation *)newLocation
           fromLocation:(CLLocation *)oldLocation
{
  int degrees = newLocation.coordinate.latitude;
  double decimal = fabs(newLocation.coordinate.latitude - degrees);
  int minutes = decimal * 60;
  double seconds = decimal * 3600 - minutes * 60;
  NSString *lat = [NSString stringWithFormat:@"%d° %d' %1.4f\"", 
           degrees, minutes, seconds];
  statusText.text = lat;
  degrees = newLocation.coordinate.longitude;
  decimal = fabs(newLocation.coordinate.longitude - degrees);
  minutes = decimal * 60;
  seconds = decimal * 3600 - minutes * 60;
  NSString *longt = [NSString stringWithFormat:@"%d° %d' %1.4f\"", 
             degrees, minutes, seconds];
  statusText.text = longt;


}

- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
    double latitude = 0, longitude = 0;
    NSString *esc_addr =  [statusText.text stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
    NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
    if (result) {
        NSScanner *scanner = [NSScanner scannerWithString:result];
        if ([scanner scanUpToString:@"\"lat\":" intoString:nil] && [scanner scanString:@"\"lat\":" intoString:nil]) {
            [scanner scanDouble:&latitude];
            if ([scanner scanUpToString:@"\"lng\":" intoString:nil] && [scanner scanString:@"\"lng\":" intoString:nil]) {
                [scanner scanDouble:&longitude];
            }
        }
    }
    CLLocationCoordinate2D center;
    center.latitude = latitude;
    center.longitude = longitude;
    return center;
}



// Implement viewDidLoad to do additional setup after loading the view, typically from a nib.
- (void)viewDidLoad {
    [super viewDidLoad];
  locationManager = [[CLLocationManager alloc] init];
  locationManager.delegate = self;
  locationManager.distanceFilter = kCLDistanceFilterNone; // whenever we move
  locationManager.desiredAccuracy = kCLLocationAccuracyHundredMeters; // 100 m
  [locationManager startUpdatingLocation];

In order: Grabbing the long and lat, Converting it with Google Map API and calling the locationManager first of all when the app launches.

The coordinates appear just simply converting them to an actual location does not happen

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评论(3

你曾走过我的故事 2024-10-11 20:23:39
  - (void)locationManager:(CLLocationManager *)manager
      didUpdateToLocation:(CLLocation *)newLocation
             fromLocation:(CLLocation *)oldLocation

该委托不适用于某些 iOS SDK。您是否在设备中对其进行了测试并进行了检查。

  - (void)locationManager:(CLLocationManager *)manager
      didUpdateToLocation:(CLLocation *)newLocation
             fromLocation:(CLLocation *)oldLocation

This delegate will not work on some iOS SDK's. Have you test it in device and checked.

殊姿 2024-10-11 20:23:39

MapKit 中有一个名为 MKReverseGeocoder 的类。您可以使用收到的位置坐标对其进行初始化并启动它。它将从其委托返回一个 MKPlacemark。使用 MKPlacemark 访问地址、城市、州、邮政编码、国家/地区等信息。

There's a class in MapKit called MKReverseGeocoder. You initialize it with the coordinate of the location you received and start it up. It will return a MKPlacemark from its delegate. Use MKPlacemark to access things like address, city, state, postal code, country etc.

后来的我们 2024-10-11 20:23:39

您还可以获取美国和其他一些国家的免费邮政编码数据库(包括纬度/经度),然后测试最近的邮政编码数据库。这样就不再依赖 API。

You can also grab a free zipcode database in for US and some others, (which includes lat/longitudes) then test for nearest. Then there's no reliance on API's.

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