#c strcmp() 没有正常工作

发布于 2024-10-04 16:36:40 字数 1065 浏览 1 评论 0原文

我想比较两个 char* 所以我用 strcmp 来做，看，在调试模式下，strcmp 中的两个 char* 获得相同的值，但仍然如此不会返回 0，并且它会跳过 if() 条件而不是输入它：

这里来自调试器的图片： http://img405.imageshack.us/img405/5218/111fi.jpg

Company FindCompany(CompanyL pcompanyList, int companyIdentityDigit) 
{
    Company companyFound;
    char *psearchWord;
    psearchWord = (char*)malloc(10*sizeof(char));

    switch(companyIdentityDigit) {
        case 0: 
            strcpy(psearchWord , "Pelephone");
            break;
        case 2: 
            strcpy(psearchWord , "Cellcom");
            break;
        case 4: 
            strcpy(psearchWord , "Orange");
            break;
    }

    while(pcompanyList->next != NULL)   {
        if(strcmp(pcompanyList->thisCompany->pcompany , psearchWord) == 0)  {
            free(psearchWord);
            return pcompanyList->thisCompany;
        }
        pcompanyList = pcompanyList->next;
    }
    free(psearchWord);
    return NULL;
}

这是为什么？

原文

I want to compare between two char* so i do it with strcmp,
look, in debugging mode, both char* in strcmp gets the same value and still it
wont return 0, and it jumps over the if() condition instead of entering it:

here pic from the debugger:
http://img405.imageshack.us/img405/5218/111fi.jpg

Company FindCompany(CompanyL pcompanyList, int companyIdentityDigit) 
{
    Company companyFound;
    char *psearchWord;
    psearchWord = (char*)malloc(10*sizeof(char));

    switch(companyIdentityDigit) {
        case 0: 
            strcpy(psearchWord , "Pelephone");
            break;
        case 2: 
            strcpy(psearchWord , "Cellcom");
            break;
        case 4: 
            strcpy(psearchWord , "Orange");
            break;
    }

    while(pcompanyList->next != NULL)   {
        if(strcmp(pcompanyList->thisCompany->pcompany , psearchWord) == 0)  {
            free(psearchWord);
            return pcompanyList->thisCompany;
        }
        pcompanyList = pcompanyList->next;
    }
    free(psearchWord);
    return NULL;
}

why is it??

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╭⌒浅淡时光〆 2024-10-11 16:36:40

尝试一个简单的 for 循环来一次打印出 pcompanyList->thisCompany->pcompany 中的字符：

for (int x = 0; x < strlen(pcompanyList->thisCompany->pcompany); x++)
    printf("%c ", pcompanyList->thisCompany->pcompany[x]);

您可以执行此操作或检查每个字符串的长度以确保没有未显示的隐藏字符检查字符串时在调试器中启动。

Try a simple for loop to print out the characters in pcompanyList->thisCompany->pcompany one at a time:

for (int x = 0; x < strlen(pcompanyList->thisCompany->pcompany); x++)
    printf("%c ", pcompanyList->thisCompany->pcompany[x]);

You can do this or check the length of each string to make sure there aren't hidden characters that aren't showing up in the debugger when you check the strings.

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