php 将链接包裹在单词周围

Question

你好，我想在这个代码块中的给定月份将谷歌搜索链接标签包裹在每个要种植的食物周围。但不想手动写出所有 a href 标签，因为我需要执行几个与此类似的块，这将非常耗时。有没有办法让 php 使用 preg_replace 之类的东西来做到这一点？

        <?php switch(date(n)) {
    case 1:
        echo "Garlic, Onion";
        break;
    case 2:
        echo "Cabbage, Carrot, Garlic, Leek, Pea, Wheat";
        break;
    case 3:
        echo "Cabbage, Carrot, Chives, Aubergine, Garlic, Leek, Lettuce, Pea, Rhubarb, Spinach, Tomato";
        break;
    case 4:
        echo "Cabbage, Carrot, Chives, Cucumber, Aubergine, Garlic, Leek, Lettuce, Pea, Pumpkin, Rhubarb, Spinach, Tomato, courgette";
        break;
    case 5:
        echo "Asparagus, Broad Beans, Cabbage, Carrot, Chives, Cucumber, Leek, Lettuce, Oregano, Pea, Pumpkin, Rhubarb, Spinach, Tomato, courgette";
        break;
    case 6:
        echo "Asparagus, Broad Beans, Cabbage, Carrot, Cucumber, Kale, Lettuce, Oregano, Pea, Pumpkin, Rhubarb, Sage, Spinach, Tomato, courgette";
        break;
    case 7:
        echo "Asparagus, Broad Beans, Broccoli, Brussel Sprouts, Cabbage, Carrot, Cauliflower, Cucumber, Kale, Oregano, Parsley, Rhubarb, Sage";
        break;
    case 8:
        echo "Asparagus, Broccoli, Brussel Sprouts, Cabbage, Carrot, Cauliflower, Kale, Oregano, Parsley, Sage";
        break;
    case 9:
        echo "Asparagus, Broccoli, Brussel Sprouts, Cabbage, Carrot, Cauliflower, Kale, Oregano, Parsley";
        break;
    case 10:
        echo "Cabbage, Onion, Parsley";
        break;
    case 11:
        echo "Apples, Garlic, Onion";
        break;
    case 12:
        echo "Apples, Garlic, Onion";
        break;
    }?>

例如，对于 12 月的情况 12，我希望该行为：

echo "<a href='http://www.google.co.uk/search?q=Apples'>Apples</a>, <a href='http://www.google.co.uk/search?q=Garlic'>Garlic</a>, <a href='http://www.google.co.uk/search?q=Onion'>Onion</a>";

Answer 1

如果只是没有标点符号的单词，您可以使用一些正则表达式魔法：

function renderGoogleLinks($line) {
    return preg_replace('/([^[:punct:]\s\t\n\r]+)/', '<a href="http://www.google.co.uk/search?q=\\1">\\1</a>', $line);
}

echo renderGoogleLinks("Apples, Garlic, Onion");

Answer 2

这是使用数组的另一种解决方案：

<?php

$plants = array(
    1  => array('Garlic', 'Onion'),
    2  => array('Cabbage', 'Carrot', 'Garlic', 'Leek', 'Pea', 'Wheat'),
    3  => array('Cabbage', 'Carrot', 'Chives', 'Aubergine', 'Garlic', 'Leek', 'Lettuce', 'Pea', 'Rhubarb', 'Spinach', 'Tomato'),
    4  => array('Cabbage', 'Carrot', 'Chives', 'Cucumber', 'Aubergine', 'Garlic', 'Leek', 'Lettuce', 'Pea', 'Pumpkin', 'Rhubarb', 'Spinach', 'Tomato', 'courgette'),
    5  => array('Asparagus', 'Broad Beans', 'Cabbage', 'Carrot', 'Chives', 'Cucumber', 'Leek', 'Lettuce', 'Oregano', 'Pea', 'Pumpkin', 'Rhubarb', 'Spinach', 'Tomato', 'courgette'),
    6  => array('Asparagus', 'Broad Beans', 'Cabbage', 'Carrot', 'Cucumber', 'Kale', 'Lettuce', 'Oregano', 'Pea', 'Pumpkin', 'Rhubarb', 'Sage', 'Spinach', 'Tomato', 'courgette'),
    7  => array('Asparagus', 'Broad Beans', 'Broccoli', 'Brussel Sprouts', 'Cabbage', 'Carrot', 'Cauliflower', 'Cucumber', 'Kale', 'Oregano', 'Parsley', 'Rhubarb', 'Sage'),
    8  => array('Asparagus', 'Broccoli', 'Brussel Sprouts', 'Cabbage', 'Carrot', 'Cauliflower', 'Kale', 'Oregano', 'Parsley', 'Sage'),
    9  => array('Asparagus', 'Broccoli', 'Brussel Sprouts', 'Cabbage', 'Carrot', 'Cauliflower', 'Kale', 'Oregano', 'Parsley'),
    10 => array('Cabbage', 'Onion', 'Parsley'),
    11 => array('Apples', 'Garlic', 'Onion'),
    12 => array('Apples', 'Garlic', 'Onion'),
);

function googleLink($myarray) {
    $str = '';
    foreach($myarray as $var) {
        $end  = (next($myarray) == true) ? ', ' : '.';
        $str .= '<a href="http://www.google.co.uk/search?q='.$var.'">'.$var.'</a>'.$end;
    }
    return $str;
}

echo googleLink($plants[date(n)]);

?>

Answer 3

首先，更改 echo 语句以将它们存储在变量中。 （并丢失空格）就像这样：

$food = "Apples,Garlic,Onion";

IDE 中的查找替换应该可以快速解决这个问题。然后在 switch 块之后执行以下操作：

$foods = explode(',', $food);
foreach ($foods as $food) {
    echo '<a href="http://www.google.co.uk/search?q=';
    echo $food;
    echo '">' . $food . '</a>, ';
}

这实际上会留下一个训练逗号和空格。因此，您可能希望首先将字符串连接到新变量中，修剪尾随空格，然后回显它。但这将帮助您开始。

Answer 4

function renderGoogleLink($searchTerm){
     $anchor_template = '<a href="http://www.google.co.uk/search?q=#TERM#">#TERM#</a>';
     echo preg_replace("#TERM#", $searchTerm, $anchor_template);
}