从双表生成 UUID

发布于 2024-10-04 13:14:58 字数 3750 浏览 1 评论 0原文

我想为唯一的字符串生成 UUID,我使用以下代码:-

thread.createSession();
HexGenerator gen1 = new HexGenerator();
gen1.setHexId("2");
thread.ses.save(gen1);
gen1 = (HexGenerator) thread.ses.load(HexGenerator.class, gen1.getHexId());
System.out.println("gen1-->" + gen1.getHexId());
thread.commit();

下面是我的休眠文件:-

<class name="entity.HexGenerator" table="dual">
    <id name="hexId" type="string" unsaved-value="null">
        <generator class="uuid.hex"/>
    </id>
</class>

UUId 已正确生成,但在提交完整事务时出现错误。如出现以下错误。

Exception in thread "main" - Could not synchronize database state with session
org.hibernate.exception.SQLGrammarException: Could not execute JDBC batch update
    at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:67)
    at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:253)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:237)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141)
    at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:298)
    at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
    at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000)
    at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:338)
    at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
    at com.ofss.test.hibernate.HibernateThread.commit(HibernateThread.java:29)
    at com.ofss.test.hibernate.HibernateThread.main(HibernateThread.java:57)
Caused by: java.sql.BatchUpdateException: ORA-00904: "HEXID": invalid identifier

    at oracle.jdbc.driver.DatabaseError.throwBatchUpdateException(DatabaseError.java:343)
    at oracle.jdbc.driver.OraclePreparedStatement.executeBatch(OraclePreparedStatement.java:10698)
    at org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:48)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:246)
    ... 9 more
org.hibernate.exception.SQLGrammarException: Could not execute JDBC batch update
    at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:67)
    at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:253)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:237)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141)
    at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:298)
    at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
    at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000)
    at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:338)
    at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
    at com.ofss.test.hibernate.HibernateThread.commit(HibernateThread.java:29)
    at com.ofss.test.hibernate.HibernateThread.main(HibernateThread.java:57)
Caused by: java.sql.BatchUpdateException: ORA-00904: "HEXID": invalid identifier

    at oracle.jdbc.driver.DatabaseError.throwBatchUpdateException(DatabaseError.java:343)
    at oracle.jdbc.driver.OraclePreparedStatement.executeBatch(OraclePreparedStatement.java:10698)
    at org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:48)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:246)

I want to generate UUID for a unique string, i am using the following code:-

thread.createSession();
HexGenerator gen1 = new HexGenerator();
gen1.setHexId("2");
thread.ses.save(gen1);
gen1 = (HexGenerator) thread.ses.load(HexGenerator.class, gen1.getHexId());
System.out.println("gen1-->" + gen1.getHexId());
thread.commit();

Below is my hibernate file:-

<class name="entity.HexGenerator" table="dual">
    <id name="hexId" type="string" unsaved-value="null">
        <generator class="uuid.hex"/>
    </id>
</class>

UUId is generated properly, but i am getting an error when the complete transaction is committed. as in the following error comes.

Exception in thread "main" - Could not synchronize database state with session
org.hibernate.exception.SQLGrammarException: Could not execute JDBC batch update
    at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:67)
    at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:253)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:237)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141)
    at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:298)
    at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
    at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000)
    at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:338)
    at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
    at com.ofss.test.hibernate.HibernateThread.commit(HibernateThread.java:29)
    at com.ofss.test.hibernate.HibernateThread.main(HibernateThread.java:57)
Caused by: java.sql.BatchUpdateException: ORA-00904: "HEXID": invalid identifier

    at oracle.jdbc.driver.DatabaseError.throwBatchUpdateException(DatabaseError.java:343)
    at oracle.jdbc.driver.OraclePreparedStatement.executeBatch(OraclePreparedStatement.java:10698)
    at org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:48)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:246)
    ... 9 more
org.hibernate.exception.SQLGrammarException: Could not execute JDBC batch update
    at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:67)
    at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:253)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:237)
    at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:141)
    at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:298)
    at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
    at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000)
    at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:338)
    at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:106)
    at com.ofss.test.hibernate.HibernateThread.commit(HibernateThread.java:29)
    at com.ofss.test.hibernate.HibernateThread.main(HibernateThread.java:57)
Caused by: java.sql.BatchUpdateException: ORA-00904: "HEXID": invalid identifier

    at oracle.jdbc.driver.DatabaseError.throwBatchUpdateException(DatabaseError.java:343)
    at oracle.jdbc.driver.OraclePreparedStatement.executeBatch(OraclePreparedStatement.java:10698)
    at org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:48)
    at org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:246)

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评论(3

陌上芳菲 2024-10-11 13:14:58

您无法在 Oracle dual 虚拟表上进行插入或更新。您只需在 select 查询中使用它即可。
因此,您的行 thread.ses.save(gen1) 就是生成错误的原因。我认为如果你删除这一行,错误就会被修复。

但我不太明白为什么你需要访问数据库来生成你的 UUID,它似乎是在 HexGenerator 类中生成的(或者可能是在 hibernate 文件引用的“uuid.gen”类中生成的)。

You can't insert or update on the Oracle dual virtual table. You just can use it at select queries.
So, your line thread.ses.save(gen1) is what generates the error. I think that if you just delete this line, the error will be fixed.

But I don't really understand why you need to access the database to generate your UUID, which seems to be generated at the HexGenerator class (or maybe at the "uuid.gen" class referenced at the hibernate file).

是伱的 2024-10-11 13:14:58

为了克服上述问题,我的意思是生成UUID,现在我决定使用两种方法,要么使用 java.util.UUID.randomUUID() 要么编写自己的逻辑来生成使用位数组相同,然后将其随机化。

To overcome the above problem, i mean to generate the UUID, now I have decided to use two method, either to use java.util.UUID.randomUUID() or to write my own logic to generate the same using bits array and then randomizing it.

最单纯的乌龟 2024-10-11 13:14:58

首先,你的代码看起来有点奇怪。您创建 HexGenerator 的实例:

HexGenerator gen1 = new HexGenerator();

使用它并立即使用一些对我来说未知的使用动态类加载的 API 进行覆盖。

thread.ses.load(HexGenerator.class, gen1.getHexId())

然后再次调用 getHexId()。我相信代码

new HexGenerator().getHexId() 

会生成您需要的 ID。

但我认为这还不是失败的原因。不幸的是,您没有提供有关数据库架构的任何信息。我相信你的ID只是定义为数字,它不能接受字符串。再次检查,如果不是这个原因,请提供更多详细信息。

first, your code looks a little bit strange. You create instance of HexGenerator:

HexGenerator gen1 = new HexGenerator();

use it and immediately override using some unknown for me API that uses dynamic class loading.

thread.ses.load(HexGenerator.class, gen1.getHexId())

Then you call getHexId() again. I believe that code

new HexGenerator().getHexId() 

will generate ID that you need.

But I think it is not yet the reason for failure. Unfortunately you did not provide any information about you DB schema. I believe that you ID is simply defined as number, it cannot accept strings. Check it again and please provide more details if this is not the reason.

~没有更多了~
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