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查找包含给定文件的文件系统的大小和可用空间

发布于 2024-10-04 05:08:55 字数 390 浏览 3 评论 0原文

我在 Linux 上使用 Python 2.6。最快的方法是什么：

确定哪个分区包含给定的目录或文件？
例如，假设/dev/sda2挂载在/home上，/dev/mapper/foo挂载在<代码>/home/foo。从字符串 "/home/foo/bar/baz" 我想恢复对 ("/dev/mapper/foo", "home/foo") .
然后，获取给定分区的使用统计信息？例如，给定 /dev/mapper/foo 我想获取分区的大小和可用空间（以字节为单位或大约以兆字节为单位）。

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第七度阳光i 2024-10-11 05:08:55

这不会给出分区的名称，但您可以使用 statvfs Unix 系统调用直接获取文件系统统计信息。要从 Python 调用它，请使用 os.statvfs （'/home/foo/bar/baz'）。

结果中的相关字段，根据 POSIX：

unsigned long f_frsize 基本文件系统块大小。 
fsblkcnt_t f_blocks 文件系统上的块总数（以 f_frsize 为单位）。 
fsblkcnt_t f_bfree 空闲块总数。 
fsblkcnt_t f_bavail 可用的空闲块数 
                         非特权进程。

因此，要理解这些值，请乘以 f_frsize：

import os
statvfs = os.statvfs('/home/foo/bar/baz')

statvfs.f_frsize * statvfs.f_blocks     # Size of filesystem in bytes
statvfs.f_frsize * statvfs.f_bfree      # Actual number of free bytes
statvfs.f_frsize * statvfs.f_bavail     # Number of free bytes that ordinary users
                                        # are allowed to use (excl. reserved space)

This doesn't give the name of the partition, but you can get the filesystem statistics directly using the statvfs Unix system call. To call it from Python, use os.statvfs('/home/foo/bar/baz').

The relevant fields in the result, according to POSIX:

unsigned long f_frsize   Fundamental file system block size. 
fsblkcnt_t    f_blocks   Total number of blocks on file system in units of f_frsize. 
fsblkcnt_t    f_bfree    Total number of free blocks. 
fsblkcnt_t    f_bavail   Number of free blocks available to 
                         non-privileged process.

So to make sense of the values, multiply by f_frsize:

import os
statvfs = os.statvfs('/home/foo/bar/baz')

statvfs.f_frsize * statvfs.f_blocks     # Size of filesystem in bytes
statvfs.f_frsize * statvfs.f_bfree      # Actual number of free bytes
statvfs.f_frsize * statvfs.f_bavail     # Number of free bytes that ordinary users
                                        # are allowed to use (excl. reserved space)

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变身佩奇 2024-10-11 05:08:55

从 Python 3.3 开始，有一种简单直接的方法可以使用标准库来执行此操作：

$ cat free_space.py 
#!/usr/bin/env python3

import shutil

total, used, free = shutil.disk_usage(__file__)
print(total, used, free)

$ ./free_space.py 
1007870246912 460794834944 495854989312

这些数字以字节为单位。有关详细信息，请参阅文档。

As of Python 3.3, there an easy and direct way to do this with the standard library:

$ cat free_space.py 
#!/usr/bin/env python3

import shutil

total, used, free = shutil.disk_usage(__file__)
print(total, used, free)

$ ./free_space.py 
1007870246912 460794834944 495854989312

These numbers are in bytes. See the documentation for more info.

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向地狱狂奔 2024-10-11 05:08:55

如果您只需要设备上的可用空间，请使用下面的 os.statvfs() 查看答案。

如果您还需要与文件关联的设备名称和挂载点，您应该调用外部程序来获取此信息。 df 将提供您需要的所有信息 - 当以 df filename 调用时，它会打印一行有关包含该文件的分区的信息。

举个例子：

import subprocess
df = subprocess.Popen(["df", "filename"], stdout=subprocess.PIPE)
output = df.communicate()[0]
device, size, used, available, percent, mountpoint = \
    output.split("\n")[1].split()

请注意，这相当脆弱，因为它取决于 df 输出的确切格式，但我不知道有更强大的解决方案。（有一些依赖于下面的 /proc 文件系统的解决方案，它们的可移植性甚至比这个还要差。）

If you just need the free space on a device, see the answer using os.statvfs() below.

If you also need the device name and mount point associated with the file, you should call an external program to get this information. df will provide all the information you need -- when called as df filename it prints a line about the partition that contains the file.

To give an example:

import subprocess
df = subprocess.Popen(["df", "filename"], stdout=subprocess.PIPE)
output = df.communicate()[0]
device, size, used, available, percent, mountpoint = \
    output.split("\n")[1].split()

Note that this is rather brittle, since it depends on the exact format of the df output, but I'm not aware of a more robust solution. (There are a few solutions relying on the /proc filesystem below that are even less portable than this one.)

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允世 2024-10-11 05:08:55

import os

def get_mount_point(pathname):
    "Get the mount point of the filesystem containing pathname"
    pathname= os.path.normcase(os.path.realpath(pathname))
    parent_device= path_device= os.stat(pathname).st_dev
    while parent_device == path_device:
        mount_point= pathname
        pathname= os.path.dirname(pathname)
        if pathname == mount_point: break
        parent_device= os.stat(pathname).st_dev
    return mount_point

def get_mounted_device(pathname):
    "Get the device mounted at pathname"
    # uses "/proc/mounts"
    pathname= os.path.normcase(pathname) # might be unnecessary here
    try:
        with open("/proc/mounts", "r") as ifp:
            for line in ifp:
                fields= line.rstrip('\n').split()
                # note that line above assumes that
                # no mount points contain whitespace
                if fields[1] == pathname:
                    return fields[0]
    except EnvironmentError:
        pass
    return None # explicit

def get_fs_freespace(pathname):
    "Get the free space of the filesystem containing pathname"
    stat= os.statvfs(pathname)
    # use f_bfree for superuser, or f_bavail if filesystem
    # has reserved space for superuser
    return stat.f_bfree*stat.f_bsize

我的计算机上的一些示例路径名：

path 'trash':
  mp /home /dev/sda4
  free 6413754368
path 'smov':
  mp /mnt/S /dev/sde
  free 86761562112
path '/usr/local/lib':
  mp / rootfs
  free 2184364032
path '/proc/self/cmdline':
  mp /proc proc
  free 0

PS

如果在 Python ≥3.3 上，则 shutil.disk_usage(path) 返回一个 (total,used, free) 的命名元组，表示为字节。

import os

def get_mount_point(pathname):
    "Get the mount point of the filesystem containing pathname"
    pathname= os.path.normcase(os.path.realpath(pathname))
    parent_device= path_device= os.stat(pathname).st_dev
    while parent_device == path_device:
        mount_point= pathname
        pathname= os.path.dirname(pathname)
        if pathname == mount_point: break
        parent_device= os.stat(pathname).st_dev
    return mount_point

def get_mounted_device(pathname):
    "Get the device mounted at pathname"
    # uses "/proc/mounts"
    pathname= os.path.normcase(pathname) # might be unnecessary here
    try:
        with open("/proc/mounts", "r") as ifp:
            for line in ifp:
                fields= line.rstrip('\n').split()
                # note that line above assumes that
                # no mount points contain whitespace
                if fields[1] == pathname:
                    return fields[0]
    except EnvironmentError:
        pass
    return None # explicit

def get_fs_freespace(pathname):
    "Get the free space of the filesystem containing pathname"
    stat= os.statvfs(pathname)
    # use f_bfree for superuser, or f_bavail if filesystem
    # has reserved space for superuser
    return stat.f_bfree*stat.f_bsize

Some sample pathnames on my computer:

path 'trash':
  mp /home /dev/sda4
  free 6413754368
path 'smov':
  mp /mnt/S /dev/sde
  free 86761562112
path '/usr/local/lib':
  mp / rootfs
  free 2184364032
path '/proc/self/cmdline':
  mp /proc proc
  free 0

PS

if on Python ≥3.3, there's shutil.disk_usage(path) which returns a named tuple of (total, used, free) expressed in bytes.

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独孤求败 2024-10-11 05:08:55

这应该满足您所要求的一切：

import os
from collections import namedtuple

disk_ntuple = namedtuple('partition',  'device mountpoint fstype')
usage_ntuple = namedtuple('usage',  'total used free percent')

def disk_partitions(all=False):
    """Return all mountd partitions as a nameduple.
    If all == False return phyisical partitions only.
    """
    phydevs = []
    f = open("/proc/filesystems", "r")
    for line in f:
        if not line.startswith("nodev"):
            phydevs.append(line.strip())

    retlist = []
    f = open('/etc/mtab', "r")
    for line in f:
        if not all and line.startswith('none'):
            continue
        fields = line.split()
        device = fields[0]
        mountpoint = fields[1]
        fstype = fields[2]
        if not all and fstype not in phydevs:
            continue
        if device == 'none':
            device = ''
        ntuple = disk_ntuple(device, mountpoint, fstype)
        retlist.append(ntuple)
    return retlist

def disk_usage(path):
    """Return disk usage associated with path."""
    st = os.statvfs(path)
    free = (st.f_bavail * st.f_frsize)
    total = (st.f_blocks * st.f_frsize)
    used = (st.f_blocks - st.f_bfree) * st.f_frsize
    try:
        percent = ret = (float(used) / total) * 100
    except ZeroDivisionError:
        percent = 0
    # NB: the percentage is -5% than what shown by df due to
    # reserved blocks that we are currently not considering:
    # http://goo.gl/sWGbH
    return usage_ntuple(total, used, free, round(percent, 1))


if __name__ == '__main__':
    for part in disk_partitions():
        print part
        print "    %s\n" % str(disk_usage(part.mountpoint))

在我的盒子上，上面的代码打印：

giampaolo@ubuntu:~/dev$ python foo.py 
partition(device='/dev/sda3', mountpoint='/', fstype='ext4')
    usage(total=21378641920, used=4886749184, free=15405903872, percent=22.9)

partition(device='/dev/sda7', mountpoint='/home', fstype='ext4')
    usage(total=30227386368, used=12137168896, free=16554737664, percent=40.2)

partition(device='/dev/sdb1', mountpoint='/media/1CA0-065B', fstype='vfat')
    usage(total=7952400384, used=32768, free=7952367616, percent=0.0)

partition(device='/dev/sr0', mountpoint='/media/WB2PFRE_IT', fstype='iso9660')
    usage(total=695730176, used=695730176, free=0, percent=100.0)

partition(device='/dev/sda6', mountpoint='/media/Dati', fstype='fuseblk')
    usage(total=914217758720, used=614345637888, free=299872120832, percent=67.2)

This should make everything you asked:

import os
from collections import namedtuple

disk_ntuple = namedtuple('partition',  'device mountpoint fstype')
usage_ntuple = namedtuple('usage',  'total used free percent')

def disk_partitions(all=False):
    """Return all mountd partitions as a nameduple.
    If all == False return phyisical partitions only.
    """
    phydevs = []
    f = open("/proc/filesystems", "r")
    for line in f:
        if not line.startswith("nodev"):
            phydevs.append(line.strip())

    retlist = []
    f = open('/etc/mtab', "r")
    for line in f:
        if not all and line.startswith('none'):
            continue
        fields = line.split()
        device = fields[0]
        mountpoint = fields[1]
        fstype = fields[2]
        if not all and fstype not in phydevs:
            continue
        if device == 'none':
            device = ''
        ntuple = disk_ntuple(device, mountpoint, fstype)
        retlist.append(ntuple)
    return retlist

def disk_usage(path):
    """Return disk usage associated with path."""
    st = os.statvfs(path)
    free = (st.f_bavail * st.f_frsize)
    total = (st.f_blocks * st.f_frsize)
    used = (st.f_blocks - st.f_bfree) * st.f_frsize
    try:
        percent = ret = (float(used) / total) * 100
    except ZeroDivisionError:
        percent = 0
    # NB: the percentage is -5% than what shown by df due to
    # reserved blocks that we are currently not considering:
    # http://goo.gl/sWGbH
    return usage_ntuple(total, used, free, round(percent, 1))


if __name__ == '__main__':
    for part in disk_partitions():
        print part
        print "    %s\n" % str(disk_usage(part.mountpoint))

On my box the code above prints:

giampaolo@ubuntu:~/dev$ python foo.py 
partition(device='/dev/sda3', mountpoint='/', fstype='ext4')
    usage(total=21378641920, used=4886749184, free=15405903872, percent=22.9)

partition(device='/dev/sda7', mountpoint='/home', fstype='ext4')
    usage(total=30227386368, used=12137168896, free=16554737664, percent=40.2)

partition(device='/dev/sdb1', mountpoint='/media/1CA0-065B', fstype='vfat')
    usage(total=7952400384, used=32768, free=7952367616, percent=0.0)

partition(device='/dev/sr0', mountpoint='/media/WB2PFRE_IT', fstype='iso9660')
    usage(total=695730176, used=695730176, free=0, percent=100.0)

partition(device='/dev/sda6', mountpoint='/media/Dati', fstype='fuseblk')
    usage(total=914217758720, used=614345637888, free=299872120832, percent=67.2)

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疏忽 2024-10-11 05:08:55

最简单的方法来找出它。

import os
from collections import namedtuple

DiskUsage = namedtuple('DiskUsage', 'total used free')

def disk_usage(path):
    """Return disk usage statistics about the given path.

    Will return the namedtuple with attributes: 'total', 'used' and 'free',
    which are the amount of total, used and free space, in bytes.
    """
    st = os.statvfs(path)
    free = st.f_bavail * st.f_frsize
    total = st.f_blocks * st.f_frsize
    used = (st.f_blocks - st.f_bfree) * st.f_frsize
    return DiskUsage(total, used, free)

The simplest way to find out it.

import os
from collections import namedtuple

DiskUsage = namedtuple('DiskUsage', 'total used free')

def disk_usage(path):
    """Return disk usage statistics about the given path.

    Will return the namedtuple with attributes: 'total', 'used' and 'free',
    which are the amount of total, used and free space, in bytes.
    """
    st = os.statvfs(path)
    free = st.f_bavail * st.f_frsize
    total = st.f_blocks * st.f_frsize
    used = (st.f_blocks - st.f_bfree) * st.f_frsize
    return DiskUsage(total, used, free)

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四叶草在未来唯美盛开 2024-10-11 05:08:55

对于问题的第二部分，“获取给定分区的使用统计信息”， psutil 使使用 disk_usage(path) 函数即可轻松完成此操作。给定一个路径，disk_usage() 返回一个命名元组，其中包括以字节表示的总空间、已用空间和可用空间，以及使用百分比。

文档中的简单示例：

>>> import psutil
>>> psutil.disk_usage('/')
sdiskusage(total=21378641920, used=4809781248, free=15482871808, percent=22.5)

Psutil 适用于从 2.6 到 3.6 的 Python 版本以及 Linux、Windows 和 OSX 等平台。

For the second part of your question, "get usage statistics of the given partition", psutil makes this easy with the disk_usage(path) function. Given a path, disk_usage() returns a named tuple including total, used, and free space expressed in bytes, plus the percentage usage.

Simple example from documentation:

>>> import psutil
>>> psutil.disk_usage('/')
sdiskusage(total=21378641920, used=4809781248, free=15482871808, percent=22.5)

Psutil works with Python versions from 2.6 to 3.6 and on Linux, Windows, and OSX among other platforms.

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Bonjour°[大白 2024-10-11 05:08:55

对于第一点，您可以尝试使用 os.path .realpath 要获取规范路径，请对照 /etc/mtab 检查它（我实际上建议调用 getmntent，但我可以' t 找到正常的方式来访问它）来找到最长的匹配。（当然，您应该 stat 文件和假定的安装点来验证它们实际上位于同一设备上）

对于第二点，请使用 os.statvfs 获取块大小和使用信息。

（免责声明：我没有测试过这些，我所知道的大部分内容都来自 coreutils 来源）

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給妳壹絲溫柔 2024-10-11 05:08:55

import os

def disk_stat(path):
    disk = os.statvfs(path)
    percent = (disk.f_blocks - disk.f_bfree) * 100 / (disk.f_blocks -disk.f_bfree + disk.f_bavail) + 1
    return percent


print disk_stat('/')
print disk_stat('/data')

import os

def disk_stat(path):
    disk = os.statvfs(path)
    percent = (disk.f_blocks - disk.f_bfree) * 100 / (disk.f_blocks -disk.f_bfree + disk.f_bavail) + 1
    return percent


print disk_stat('/')
print disk_stat('/data')

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束缚ｍ 2024-10-11 05:08:55

11 年后，但扩展了其他答案。

import psutil

#File systems
value=psutil.disk_partitions()

for i in value:
    va=i[1]
    value2=psutil.disk_usage(va).percent
    print(value2)
    fs_space[va]=value2

这是将其添加到字典中，仅获取百分比，因为这正是我所需要的，但您可以获取所有值或从总数、已用值、免费值或百分比中选择您想要的值。

官方文档帮助很大

11 years later but expanding on others answers.

import psutil

#File systems
value=psutil.disk_partitions()

for i in value:
    va=i[1]
    value2=psutil.disk_usage(va).percent
    print(value2)
    fs_space[va]=value2

This is adding it to a dictionary, only grabbing percent as that is what I need, but you can grab all values or select the one you want from the total, used, free, or percent.

Official documentation helped a lot

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情泪▽动烟 2024-10-11 05:08:55

检查 Windows PC 上的磁盘使用情况可以按如下方式完成：

import psutil

fan = psutil.disk_usage(path="C:/")
print("Available: ", fan.total/1000000000)
print("Used: ", fan.used/1000000000)
print("Free: ", fan.free/1000000000)
print("Percentage Used: ", fan.percent, "%")

Checking the disk usage on your Windows PC can be done as follows:

import psutil

fan = psutil.disk_usage(path="C:/")
print("Available: ", fan.total/1000000000)
print("Used: ", fan.used/1000000000)
print("Free: ", fan.free/1000000000)
print("Percentage Used: ", fan.percent, "%")

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