如何观察打开的Popup的位置？

发布于 2024-10-04 03:13:57 字数 448 浏览 3 评论 0原文

我想打开一个弹出窗口，并在用户关闭弹出窗口或通过外部链接离开它时收到通知。

popup = window.open(
  "http://ec.europa.eu/yourvoice/ipm/forms/dispatch?form=tobacco6", 
  '',
  'status=no,resizable=no,scrollbars=no,toolbar=no,menubar=no,location=no,copyhistory=no'
);

为了检查用户是否关闭了弹出窗口，我设置了一个超时来检查弹出窗口是否打开。

if(popup.closed)

如何检查弹出窗口的位置是否仍然是最初的位置？

popup.location

只需返回 about:blank 即可。

原文

I wanted to open an popup and get notify if the user closes the Popup or leaves it through an external link.

popup = window.open(
  "http://ec.europa.eu/yourvoice/ipm/forms/dispatch?form=tobacco6", 
  '',
  'status=no,resizable=no,scrollbars=no,toolbar=no,menubar=no,location=no,copyhistory=no'
);

To check if the user closed the popup I set an Timeout that checkes if the popup is open.

if(popup.closed)

How can i check if the location of the popup is still the inital one?

popup.location

just return about:blank.

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小情绪 2024-10-11 03:13:57

您只需使用 onbeforeunload 事件即可。

popup.onbeforeunload = function(e) {
    if(!e) e = window.event;
    //e.cancelBubble is supported by IE - this will kill the bubbling process.
    e.cancelBubble = true;
    e.returnValue = 'You sure you want to leave?'; //This is displayed on the dialog

    //e.stopPropagation works in Firefox.
    if (e.stopPropagation) {
        e.stopPropagation();
        e.preventDefault();
    }
}

You can simply use the onbeforeunload event.

popup.onbeforeunload = function(e) {
    if(!e) e = window.event;
    //e.cancelBubble is supported by IE - this will kill the bubbling process.
    e.cancelBubble = true;
    e.returnValue = 'You sure you want to leave?'; //This is displayed on the dialog

    //e.stopPropagation works in Firefox.
    if (e.stopPropagation) {
        e.stopPropagation();
        e.preventDefault();
    }
}

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