Antlr 3.2 重写规则
我最近开始学习 Antlr 并下载 AntlrWorks 1.4，其中应该包含 Antlr 3.2。现在，3.2 应该支持重写规则语法，如“->”但我什至无法获得基于 Lexer 或 Parser 规则构建的最简单的情况：
grammar TestRewrite;
ab : a b -> a;
a : A;
b : B;
A : 'a';
B : 'b';
当我尝试编译它时，我收到错误：
[11:26:29] error(100): TestRewrite.g:3:13: syntax error: antlr: TestRewrite.g:3:13: unexpected token: a
为什么是这样。构造看起来很简单：ab 应该生成一棵树，其中仅捕获 a 节点。你不就是这样做的吗？我也无法让它与生根（'^'）或忽略（'！'）一起工作。我已经很迷茫了。
I've recently started learning Antlr and downloading AntlrWorks 1.4 which supposedly includes Antlr 3.2. Now, 3.2 is supposed to support the rewrite rules grammars like '->' but I've not been able to get even the simplest case I could construct to work either based on Lexer or Parser rules:
grammar TestRewrite;
ab : a b -> a;
a : A;
b : B;
A : 'a';
B : 'b';
When I try to compile this, I get the error:
[11:26:29] error(100): TestRewrite.g:3:13: syntax error: antlr: TestRewrite.g:3:13: unexpected token: a
Why is this. The construction seems simple enough: ab should generate a tree where only the a node is captured. Isn't that how you do it? I can't get it to work with rooting ('^') or ignoring ('!') either. I've very confused.
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选项 {输出=AST;}
options {output=AST;}