WPF 在进行时不更新文本框

发布于 2024-10-03 16:17:03 字数 419 浏览 3 评论 0原文

我有这样的代码：

void wait(int ms)
{
    System.Threading.Thread.Sleep(ms);
}

private void button1_Click(object sender, RoutedEventArgs e)
{
    info.Text = "step 1";
    wait(1000);
    info.Text = "step 2";
    wait(1000);
    info.Text = "step 3";
    wait(1000);
    info.Text = "step 4";
    wait(1000);
}

问题是 textbox.text 在整个 void button1_Click 完成后更新。它没有在播出中更新:(

请问，该怎么做？

原文

I have this code:

void wait(int ms)
{
    System.Threading.Thread.Sleep(ms);
}

private void button1_Click(object sender, RoutedEventArgs e)
{
    info.Text = "step 1";
    wait(1000);
    info.Text = "step 2";
    wait(1000);
    info.Text = "step 3";
    wait(1000);
    info.Text = "step 4";
    wait(1000);
}

And problem is that textbox.text is updated after whole void button1_Click finished. It is not updated ON AIR :(

Please, How to do that?

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梦魇绽荼蘼 2024-10-10 16:17:03

就这样做吧。

private void button1_Click(object sender, RoutedEventArgs e)
    {
        ThreadPool.QueueUserWorkItem((o) =>
             {
                 Dispatcher.Invoke((Action) (() => info.Text = "step 1"));
                 wait(1000);
                 Dispatcher.Invoke((Action) (() => info.Text = "step 2"));
                 wait(1000);
                 Dispatcher.Invoke((Action) (() => info.Text = "step 3"));
                 wait(1000);
                 Dispatcher.Invoke((Action) (() => info.Text = "step 4"));
                 wait(1000);
             });
    }

Just do this.

private void button1_Click(object sender, RoutedEventArgs e)
    {
        ThreadPool.QueueUserWorkItem((o) =>
             {
                 Dispatcher.Invoke((Action) (() => info.Text = "step 1"));
                 wait(1000);
                 Dispatcher.Invoke((Action) (() => info.Text = "step 2"));
                 wait(1000);
                 Dispatcher.Invoke((Action) (() => info.Text = "step 3"));
                 wait(1000);
                 Dispatcher.Invoke((Action) (() => info.Text = "step 4"));
                 wait(1000);
             });
    }

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‘画卷フ 2024-10-10 16:17:03

在 button1_Click 方法返回之前，GUI 线程不会刷新。这就是为什么您只能看到最后一个值。您必须将长方法放入异步调用中或使用线程。

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抚笙 2024-10-10 16:17:03

测量/排列（以及渲染）是异步发生的，因此如果您想强制屏幕更新，则需要调用 UpdateLayout。

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空心空情空意 2024-10-10 16:17:03

如果您尝试使用 DispatcherFrame 来模拟 DoEvents 将完成的形式会怎样：

您可能需要包含 System.Security.Permissions 和 System.Windows.Threading。之后，在每次睡眠后调用 DoEvents() 即可获得所需的结果。

[SecurityPermissionAttribute(SecurityAction.Demand, Flags = SecurityPermissionFlag.UnmanagedCode)]
public void DoEvents()
{
    DispatcherFrame frame = new DispatcherFrame();
    Dispatcher.CurrentDispatcher.BeginInvoke(DispatcherPriority.Background,
        new DispatcherOperationCallback(ExitFrame), frame);
    Dispatcher.PushFrame(frame);
}

public object ExitFrame(object f)
{
    ((DispatcherFrame)f).Continue = false;

    return null;
}

链接到 MSDN 文章：http://msdn。 microsoft.com/en-us/library/system.windows.threading.dispatcher.pushframe.aspx

What if you tried a DispatcherFrame to simulate what forms DoEvents would accomplish:

You may need to include System.Security.Permissions and System.Windows.Threading. After that pplace a call to DoEvents() after each of your sleeps and you get the desired result.

[SecurityPermissionAttribute(SecurityAction.Demand, Flags = SecurityPermissionFlag.UnmanagedCode)]
public void DoEvents()
{
    DispatcherFrame frame = new DispatcherFrame();
    Dispatcher.CurrentDispatcher.BeginInvoke(DispatcherPriority.Background,
        new DispatcherOperationCallback(ExitFrame), frame);
    Dispatcher.PushFrame(frame);
}

public object ExitFrame(object f)
{
    ((DispatcherFrame)f).Continue = false;

    return null;
}

Link to MSDN article: http://msdn.microsoft.com/en-us/library/system.windows.threading.dispatcher.pushframe.aspx

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