从字符串中删除 ()

发布于 2024-10-03 09:16:20 字数 201 浏览 5 评论 0原文

$item = "(1) Robin Hood (hero)";

括号内的文本可以更改。

如何从字符串中删除所有包含文本的括号？

我们应该得到这个：

$item = "Robin Hood";

谢谢！

$item = "(1) Robin Hood (hero)";

Text inside brackets can be changed.

How do I remove all the brackets with text inside them from the string?

We should get this:

$item = "Robin Hood";

Thanks!

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薄荷梦 2024-10-10 09:16:20

您可以将 preg_replace 用作：

$item = preg_replace('/\(.*?\)/s','',$item);

看起来您还想在替换后删除前导和尾随空格。
您可以将 trim 用作：

$item = trim( preg_replace('/\(.*?\)/s','',$item));

正则表达式使用的是 \(.*?\)：

You can use preg_replace as:

$item = preg_replace('/\(.*?\)/s','',$item);

Looks like you also want to remove leading and trailing spaces after the replacement.
You can make use of trim for that as:

$item = trim( preg_replace('/\(.*?\)/s','',$item));

The regex used is \(.*?\):

( and ) are regex meta-characters
used for grouping. To match literal
paranthesis you need to escape them
by preceding them with a \.
You match any arbitrary text between
the parenthesis by using .*?. You
could also do the same using [^)]*
. by default does not match a
newline. To make is match a newline
we use the s modifier. Without it
we would fail to do the replacement
in "(hello\nworld) Hi"