如何使用 Apache Httpclient api 获取 XML 文档响应？

Question

我可以收到回复。如何获取 XML 文档中的响应？我需要使用外部 XML 解析器吗？感谢您的帮助

DefaultHttpClient client = new DefaultHttpClient();
String getUrl = "http://myurl.com";

HttpUriRequest getRequest = new HttpGet(getUrl);

getRequest.setHeader("User-Agent",  "xxxx");

 HttpResponse response = client.execute(getRequest);
 int statusCode = response.getStatusLine().getStatusCode();

 log.info("statusCode=" + statusCode);

 if (statusCode == 200 ){
  HttpEntity entity = response.getEntity();
  String content = EntityUtils.toString(entity);
  log.info("\n" + content);
 }else {
  log.warn("failed to response");
 }

Answer 1

我得到了答案，在这里发帖给有同样问题的人

DefaultHttpClient client = new DefaultHttpClient();
String getUrl = "http://myurl.com";

HttpUriRequest getRequest = new HttpGet(getUrl);

getRequest.setHeader("User-Agent",  "xxxx");

 HttpResponse response = client.execute(getRequest);
 int statusCode = response.getStatusLine().getStatusCode();

 log.info("statusCode=" + statusCode);

Document doc = null;
        if (statusCode == 200 ){
            HttpEntity entity = response.getEntity();
            //String content = EntityUtils.toString(entity);

            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
            try {
                DocumentBuilder builder = factory.newDocumentBuilder();
                doc = builder.parse(entity.getContent());
            } catch (ParserConfigurationException e) {              
                e.printStackTrace();
            } catch (IllegalStateException e) {
                e.printStackTrace();
            } catch (SAXException e) {
                e.printStackTrace();
            }                           
        }