无法将 JSON 解码为 dataprovider

发布于 2024-10-03 08:09:37 字数 540 浏览 0 评论 0原文

我正在加载一个php文件并调用这个函数decodeJSON想要解析数据并将其显示到组合框中，但是当我进行跟踪时我得到的只是

[object Object],[object Object],[object Object]

这里是代码

    function decodeJSON(event:Event):void{
var loader2:URLLoader = URLLoader(event.target);
var jsonArray:Array = JSON.decode(loader2.data) as Array; 
var dp:DataProvider = new DataProvider();
trace(jsonArray);
combo.dataProvider = dp;
for (var i=0; i<jsonArray.length; i++) 
{ 
dp.addItem({Label: "Name="+jsonArray[i].Name});
trace(jsonArray[i].Name);
}

原文

I am loading a php file and calling this function decodeJSON want to parse the data and dispaly it into a combo box but when i do a trace all i get is

[object Object],[object Object],[object Object]

Here is the code

    function decodeJSON(event:Event):void{
var loader2:URLLoader = URLLoader(event.target);
var jsonArray:Array = JSON.decode(loader2.data) as Array; 
var dp:DataProvider = new DataProvider();
trace(jsonArray);
combo.dataProvider = dp;
for (var i=0; i<jsonArray.length; i++) 
{ 
dp.addItem({Label: "Name="+jsonArray[i].Name});
trace(jsonArray[i].Name);
}

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你好，陌生人 2024-10-10 08:09:37

所以看起来它已经解析得很好，但如果你希望它完全追踪出来，你也需要循环遍历对象。跟踪只会打印出您正在跟踪的对象的顶层。在本例中，您有一个包含 3 个元素的数组。如果您想测试它是否正确解析它，请尝试找出您知道应该在对象内的内容，例如：

trace(jsonArray[0].itemName)

so it looks like it has parsed just fine but if you want it to fully trace out you are going to need to loop through the objects as well. Trace will only print out the top level of the object you are tracing. In this case you have an array with 3 elements in it. If you want to test to see if it parsed it correctly try tracing out something that you know should be within the object like: