谷歌地图v3动态设置标记大小

Question

问题在于，我有一个数据库，其中保存有关标记图像的信息：

我正在使用 ajax 调用检索所有内容并将数据保存为对象，这样我就可以检查标记的位置类型并为该类型放置适当的标记的位置。

我接收到的数据很好，但是当我尝试将数据添加到新的谷歌地图图像的构造函数中时，它出错了，我已经检查了一个警报，确认那里有正确的信息，这是什么给出了？？？

// the following code will wor!!!
                   new google.maps.Size(32,37) // The Size works
//The following line breaks it with dynamic value    
                   new google.maps.Size(myIconArray.icon[myData.name_etp].size) 

这是完整的代码： （静态代码行中的测试值与我正在创建的对象引用中存储的值相同） http://www.focus-on-plants.com/locator_iconed.php

function addMarker(map, myData){
      console.log(myData)
      // Create the marker
      // create the marker info first
      myLatLng = new google.maps.LatLng(myData.lat_mdt, myData.lng_mdt);
      markersArray.push(myLatLng);
      markersInfoArray.push(myData);

      // ----------------------------
      // NOW CREATE THE ACTUAL ICON
       //alert( myIconArray.icon[myData.name_etp].size)

      /*var iconimage = new google.maps.MarkerImage(
       '/images/icons/markers/flower_lb/image_med.png', //myIconArray.icon[myData.name_etp].image,
       new google.maps.Size(myIconArray.icon[myData.name_etp].size) // The Size
       //new google.maps.Point(myIconArray.icon[myData.name_etp].origin), // The origin
       //new google.maps.Point(myIconArray.icon[myData.name_etp].anchorpoint) // The anchor
      );*/
      //console.log(iconimage)
      var iconshape = {
       type: 'poly',
       coord: [0,2,1,2,1,1,18,0,18,1,19,2,20,19,19,19,18,21,14,21,10,26,5,21,1,21,1,20,0,20,0,2]
      }

      //alert(myIconArray.shape[myData.name_etp])
      mySize = 'new google.maps.Size('+myIconArray.icon[myData.name_etp].size+')'
      var iconimage = new google.maps.MarkerImage(
       myIconArray.icon[myData.name_etp].image,
       // the following code works!!!
                        new google.maps.Size(32,37) // The Size works
                       //The following line breaks iot with dynamic value    
                       //new google.maps.Size(myIconArray.icon[myData.name_etp].size) 


       //new google.maps.Point(0, 0), // The origin
       //new google.maps.Point(13,29) // The anchor
      );
      var iconshadow = new google.maps.MarkerImage(
       '/images/icons/markers/flower_lb/shadow_med.png',
       new google.maps.Size(42,18), // The Size
       new google.maps.Point(0,0), // The origin
       new google.maps.Point(13,18) // The anchor
      );

      var marker = new google.maps.Marker({
       position: myLatLng,
       map: map,
       title: myData.name_mdt,
       icon: iconimage,
       shadow: iconshadow//,
       //shape: iconshape
      });

      // Wrapping the event listener inside an anonymous function
      // that we immediately invoke and passes the variable i to.
      (function(myData, marker) {
       // Creating the event listener. It now has access to the values of
       // myData and marker as they were during its creation
       google.maps.event.addListener(marker, 'click', function() {
        //create thecontent for the infowindow
        var content = createContent(myData);
        var infowindow = new google.maps.InfoWindow({
         content: content
        });
        infowindow.open(map, marker);
       });
      })(myData, marker);  

     };

Answer 1

好的，所以我找到了原因，

我传递了 new google.maps.Size(myIconArray.icon[myData.name_etp].size)

google imagemaps.size 需要两个单独的参数，new google.maps.Size(42,18)

我传递了 32, 37 这实际上是一个字符串，

我需要使用以下命令拆分字符串：

tmp = myIconArray.icon[myData.name_etp].size.split(",")

然后添加我使用的大小的 x 和 y： new google.maps.Size(tmp[0], tmp [1])