Regex TitleRegex = new Regex(@"[A-Z].* - ([0-9]{1,2}) [A-Z]");
You are capturing the . which generally is match all except new lines. I put the {1,2} quantifier there, meaning it will match 0-99. Change that to suit your requirements (or you could just leave it as 0 or more*).
Could you also use \d instead of [0-9]. Shorthand is generally a good thing :)
When you use [0-9].* it searches for one number plus 0 or many symbols, using [0-9]+ gives you one or more integers on that specific place. If you are sure there wont be more than lets say 3 integers so you can use [0-9]{1,3} or as much as you want 4,5,etc.
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您正在捕获
.，它通常匹配除换行符之外的所有内容。我将{1,2}量词放在那里，这意味着它将匹配 0-99。更改它以满足您的要求（或者您可以将其保留为0或更多*）。您还可以使用
\d而不是[0-9]吗？速记通常是一件好事:)You are capturing the
.which generally is match all except new lines. I put the{1,2}quantifier there, meaning it will match 0-99. Change that to suit your requirements (or you could just leave it as 0 or more*).Could you also use
\dinstead of[0-9]. Shorthand is generally a good thing :)之所以包含这些字母，是因为您在将
.*添加到捕获组时要求提供这些字母。尝试使用([0-9]+)或更好的(\d+)The letters are included because you asked for them when you added
.*to the capture group. Try just([0-9]+)or better(\d+)答案是你似乎滥用了量词；
该部分模式与任何单个数字 (0-9) 匹配一次，然后还匹配任何字符 (.) 0 次或多次 (*)
删除星号前的点。
The answer is that you appear to be misusing the quantifiers;
That partial pattern matches any single digit (0-9) once, and then also any character at all (.) 0 or more times (*)
Remove the dots before the asterisks.
更改为：
当您使用
[0-9].*时，它会搜索一个数字加 0 或多个符号，使用[0-9]+会搜索一个或多个符号该特定位置上的整数。如果您确定不会超过 3 个整数，那么您可以使用[0-9]{1,3}或任意数量的 4,5 等。Change to:
When you use
[0-9].*it searches for one number plus 0 or many symbols, using[0-9]+gives you one or more integers on that specific place. If you are sure there wont be more than lets say 3 integers so you can use[0-9]{1,3}or as much as you want 4,5,etc.