awk 打印没有固定宽度格式的字符串？

Question

有没有办法让 awk 不打印固定宽度的列？

例如：

"9", "TAYLOR TOWER, JACOB B.   "
"9", "UNIVERSITY HOSPITALS-EAST"
"AR", "SCHOTTENSTEIN CENTER     "
"B1", "NEWARK RESIDENCE HALL    "
"B2", "NEWARK RESIDENCE HALL    "
"CC", "OHIO STADIUM             "
"D1", "TELECOM NETWORK CENTER  "
"DC", "SCHOTTENSTEIN CENTER     "
"EN", "SCHOTTENSTEIN CENTER     "
"GR", "UNIVERSITY HOSPITALS-EAST"
"LL", "RANEY COMMONS, 2ND LT. AL"
"MZ", "PHYSICS RESEARCH        "
"MZ", "SCHOTTENSTEIN CENTER     "
"NS", "STARLING LOVING HALL    "
"P1", "OHIO STADIUM             "
"P2", "OHIO STADIUM             "
"P3", "OHIO STADIUM             "

我希望将其打印为：

"9", "TAYLOR TOWER, JACOB B."
"9", "UNIVERSITY HOSPITALS-EAST"
"AR", "SCHOTTENSTEIN CENTER"
"B1", "NEWARK RESIDENCE HALL"
"B2", "NEWARK RESIDENCE HALL"
"CC", "OHIO STADIUM"
"D1", "TELECOM NETWORK CENTER"
"DC", "SCHOTTENSTEIN CENTER"
"EN", "SCHOTTENSTEIN CENTER"
"GR", "UNIVERSITY HOSPITALS-EAST"
"LL", "RANEY COMMONS, 2ND LT. AL"
"MZ", "PHYSICS RESEARCH"
"MZ", "SCHOTTENSTEIN CENTER"
"NS", "STARLING LOVING HALL"
"P1", "OHIO STADIUM"
"P2", "OHIO STADIUM"
"P3", "OHIO STADIUM"

请注意，此文本中的第二个字段引号内没有空格。这可能吗？

Answer 1

在 AWK 中（gawk/nawk）

{sub(/[ ]*\"$/, "\"");print}

Answer 2

我会使用 sed 而不是 awk，尽管如果必须的话，您可以在 awk 中执行 gsub ：

sed -e 's/  *"$/"/'

意思是“将行末尾的一个或多个空格后跟引号变成仅引号”