多个域的 preg_replace 和数组

发布于 2024-10-02 11:18:18 字数 833 浏览 3 评论 0原文

我有一个像这样的数组：

$array =  array('domain1.com','domain2.net','domain3.org');

有什么方法可以仅将这些域替换为带有 preg_replace 的链接吗？

目前有这个小功能，但解析所有域：

                function insert_referer($text){
                    $text = preg_replace('#(script|about|applet|activex|chrome):#is', "\\1:", $text);
                    $ret = ' ' . $text;
                    $ret = preg_replace("#(^|[\n ])([\w]+?://[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"\\2\" target=\"_blank\">\\2</a>", $ret);
                    $ret = preg_replace("#(^|[\n ])((www|ftp)\.[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\2</a>", $ret);
                    $ret = substr($ret, 1);
                    return $ret;
                }

原文

i have an array like this:

$array =  array('domain1.com','domain2.net','domain3.org');

any way to replace only these domains into links with preg_replace?

currently have this little function, but parses all the domains:

                function insert_referer($text){
                    $text = preg_replace('#(script|about|applet|activex|chrome):#is', "\\1:", $text);
                    $ret = ' ' . $text;
                    $ret = preg_replace("#(^|[\n ])([\w]+?://[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"\\2\" target=\"_blank\">\\2</a>", $ret);
                    $ret = preg_replace("#(^|[\n ])((www|ftp)\.[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\2</a>", $ret);
                    $ret = substr($ret, 1);
                    return $ret;
                }

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七色彩虹 2024-10-09 11:18:18

这段代码做了你想要的：

$array = array('domain1.com','domain2.net','domain3.org');
$text = 'Some text including domain1.com/something and http://domain3.org';
echo preg_replace('/((?:https?:\/\/)?(?:' . implode('|', $array) . ')[-a-zA-Z0-9\._~:\/?#\[\]@\!\amp;\'\(\)\*\+,;=]*)/', '\1', $text);
// Outputs:
// "Some text including <a href="domain1.com/something">domain1.com/something</a> and <a href="http://domain3.org">http://domain3.org</a>"

我没有测试代码本身，所以它可能（我不认为它会，但有可能）包含拼写错误，但我测试了正则表达式本身，它工作得很好。

This code does what you wanted:

$array = array('domain1.com','domain2.net','domain3.org');
$text = 'Some text including domain1.com/something and http://domain3.org';
echo preg_replace('/((?:https?:\/\/)?(?:' . implode('|', $array) . ')[-a-zA-Z0-9\._~:\/?#\[\]@\!\\'\(\)\*\+,;=]*)/', '\1', $text);
// Outputs:
// "Some text including <a href="domain1.com/something">domain1.com/something</a> and <a href="http://domain3.org">http://domain3.org</a>"

I didn't test the code itself so it may (I don't think it would but it's possible) contain typos, but I tested the regexp itself and it works perfectly.

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