需要有关 jQuery $.inArray() 的帮助

发布于 2024-10-02 08:22:07 字数 536 浏览 8 评论 0原文

谁能告诉我这段代码有什么问题吗？

jQuery(document).ready(function(){

    var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
    var myArr = ["Weekly", "something"];

    $( myArr ).each(function( j ){
        if ( $.inArray( myArr[j] == val ) ) {
            alert( 'yes, Matched !!' );
            console.log(  myArr[j] );
        } else {
            alert( 'Nops ' );
        }
    });

    //console.log( val );
});

我需要匹配数组元素，我使用了 $.inArray()，但它永远不会进入 ELSE 条件，即使它不存在于数组中。任何帮助将不胜感激。

原文

Could anybody tell me what is wrong with this code ??

jQuery(document).ready(function(){

    var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
    var myArr = ["Weekly", "something"];

    $( myArr ).each(function( j ){
        if ( $.inArray( myArr[j] == val ) ) {
            alert( 'yes, Matched !!' );
            console.log(  myArr[j] );
        } else {
            alert( 'Nops ' );
        }
    });

    //console.log( val );
});

I need to match the array elements, i used $.inArray(), but it never goes to ELSE condition even it doesn't exist in the array.
Any help would be appreciatd.

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狼性发作 2024-10-09 08:22:07

$.inArray() 采用两个参数，即值和数组，并返回 > -1 如果找到匹配项，那么它应该是这样的：

jQuery(document).ready(function(){
   var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
   var myArr = ["Weekly", "something"];
   $.each(myArr, function(i, v) {
     if ($.inArray(v, val) != -1) {
        alert( 'yes, Matched !!' );
        console.log(v);
     } else {
        alert( 'Nops ' );
     }
   });
});

你可以在这里测试它。另请注意 $.each() 用于非元素集，没有理由创建无效的 jQuery 对象来运行循环。

$.inArray() takes two arguments, the value and the array, and returns > -1 if it finds a match, so it should be like this:

jQuery(document).ready(function(){
   var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
   var myArr = ["Weekly", "something"];
   $.each(myArr, function(i, v) {
     if ($.inArray(v, val) != -1) {
        alert( 'yes, Matched !!' );
        console.log(v);
     } else {
        alert( 'Nops ' );
     }
   });
});

You can test it here. Also note the use of $.each() for non-element sets, no reason creating an invalid jQuery object to run the loop.

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阳光的暖冬 2024-10-09 08:22:07

jQuery(document).ready(function() {

    var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
    var myArr = ["Weekly", "something"];

    $(myArr).each(function(j) {
        if ($.inArray(myArr[j], val) != -1) {
            alert('yes, Matched !!');
        } else {
            alert('Nops ');
        }
    });

});

$.inArray 当在数组中找不到值时返回 -1，否则返回数组中的位置，可能是 0代码>.

jQuery(document).ready(function() {

    var val = ["Hourly", "Daily", "Weekly", "Monthly", "Yearly"];
    var myArr = ["Weekly", "something"];

    $(myArr).each(function(j) {
        if ($.inArray(myArr[j], val) != -1) {
            alert('yes, Matched !!');
        } else {
            alert('Nops ');
        }
    });

});

$.inArray returns -1 when it doesn't find the value in the array, otherwise it returns the position in the array, which could be 0.

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