python中的str到时间

Question

time1 = "2010-04-20 10:07:30"
time2 = "2010-04-21 10:07:30"

如何将上面的字符串转换为时间戳？

我需要减去上面的时间戳time2-time1。

Answer 1

对于 Python 2.5+

from datetime import datetime
format = '%Y-%m-%d %H:%M:%S'
print datetime.strptime(time2, format) - 
        datetime.strptime(time1, format)
# 1 day, 0:00:00

编辑： 对于 Python 2.4

import time
format = '%Y-%m-%d %H:%M:%S'
print time.mktime(time.strptime(time2, format)) - 
        time.mktime(time.strptime(time1, format))
# 86400.0

Answer 2

>>> t1 = datetime.strptime(time1, "%Y-%m-%d %H:%M:%S")
>>> t2 = datetime.strptime(time2, "%Y-%m-%d %H:%M:%S")
>>> t2-t1
datetime.timedelta(1)

>>> (t2-t1).days
1
>>> (t2-t1).seconds
0

Answer 3

如果你像我一样被困在 Python 2.4 系统上：

from time import strptime
from datetime import datetime

str_to_datetime = lambda st: datetime(*strptime(st, '%Y-%m-%d %H:%M:%S')[:6])

str_to_datetime('2010-04-20 10:07:30')

否则 datetime.strptime() 会工作得很好。

Answer 4

import time

time1 = "2010-04-20 10:07:30"

time_tuple = time.strptime(time1, "%Y-%m-%d %H:%M:%S")

timestamp = time.mktime(time_tuple)