在用户等待时处理大量数据的最佳实践(在 Rails 中)?

发布于 2024-10-02 01:43:32 字数 798 浏览 1 评论 0原文

我有一个小书签,使用时会将当前浏览器页面上的所有 URL 提交到 Rails 3 应用程序进行处理。在幕后,我使用 Typhoeus 来检查每个 URL 是否返回 2XX 状态代码。目前,我通过向 Rails 服务器发出 AJAX 请求来启动此过程,然后只需等待它处理并返回结果。对于较小的集合来说,这非常快,但是当 URL 的数量相当大时,用户可能会等待长达 10-15 秒。

我考虑过使用延迟作业在用户线程之外处理此问题,但这似乎不是正确的用例。由于用户需要等到处理完成才能看到结果,并且延迟作业可能需要长达五秒的时间才能开始作业,因此我无法保证处理会尽快发生。不幸的是,在这种情况下,这个等待时间是不可接受的。

理想情况下,我认为应该发生的是这样的:

  • 用户点击小书签
  • 数据被发送到服务器进行处理
  • 等待页面立即返回,同时分出一个线程来进行处理
  • 等待页面通过 ajax 定期轮询处理结果,更新等待页面(例如:“已处理 567 个 URL 中的 4 个...”)
  • 一旦结果准备好,等待页面就会更新结果

一些额外的细节:

  • 我正在使用 Heroku(长时间运行的进程在 30 秒后被终止
  • )登录和匿名用户可以使用此功能

这是执行此操作的典型方法,还是有更好的方法?我应该滚动自己的线程外处理来在处理期间更新数据库,还是有类似延迟作业的东西可以用于此目的(并且适用于 Heroku)?任何朝正确方向的推动将不胜感激。

I have a bookmarklet that, when used, submits all of the URLs on the current browser page to a Rails 3 app for processing. Behind the scenes I'm using Typhoeus to check that each URL returns a 2XX status code. Currently I initiate this process via an AJAX request to the Rails server and simply wait while it processes and returns the results. For a small set, this is very quick, but when the number of URLs is quite large, the user can be waiting for up to, say, 10-15 seconds.

I've considered using Delayed Job to process this outside the user's thread, but this doesn't seem like quite the right use-case. Since the user needs to wait until the processing is finished to see the results and Delayed Job may take up to five seconds before the job is even started, I can't guarantee that the processing will happen as soon as possible. This wait time isn't acceptable in this case unfortunately.

Ideally, what I think should happen is this:

  • User hits bookmarklet
  • Data is sent to the server for processing
  • A waiting page is instantly returned while spinning off a thread to do the processing
  • The waiting page periodically polls via ajax for the results of the processing and updates the waiting page (ex: "4 of 567 URLs processed...")
  • the waiting page is updated with the results once they are ready

Some extra details:

  • I'm using Heroku (long running processes are killed after 30 seconds)
  • Both logged in and anonymous users can use this feature

Is this a typical way to do this, or is there a better way? Should I just roll my own off-thread processing that updates the DB during processing or is there something like Delayed Job that I can use for this (and that works on Heroku)? Any pushes in the right direction would be much appreciated.

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來不及說愛妳 2024-10-09 01:43:32

我认为你的后一个想法最有道理。我只是将每个 url 检查的处理卸载到其自己的线程(因此所有 url 检查同时运行——无论如何,这应该比顺序检查快得多)。当每个线程完成时,它都会更新数据库(确保线程不会干扰彼此的写入)。 AJAX 端点(正如您所说,您在客户端定期轮询)将从数据库获取并返回已完成进程的计数。这是一个足够简单的方法,我真的认为不需要任何额外的组件。

I think your latter idea makes the most sense. I would just offload the processing of each url-check to its own thread (so all the url checks run concurrently -- which should be a lot faster than sequential checks anyway). As each finishes, it updates the database (making sure the threads don't step on each other's writes). An AJAX endpoint -- which, as you said, you poll regularly on the client side -- will grab and return the count of completed processes from the database. This is a simple enough method that I don't really see the need for any extra components.

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