基本的OpenGL光照问题
我认为这是一个非常愚蠢和新手的问题，但我是图形和 openGL 方面的新手。绘制了一个球体并在附近放置了一个光源，还指定了环境光，我开始尝试光和材质值，并得出了一个令人惊讶的结论：我们用 glColor* 指定的颜色并不重要当照明启用时。相反，等效的是材质的环境成分。这个结论正确吗？谢谢
I think this is an extremely stupid and newbie question, but then I am a newbie in graphics and openGL. Having drawn a sphere and put a light source nearby, also having specified ambient light, I started experimenting with light and material values and came to a surprising conclusion: the colors which we specify with glColor* do not matter at all when lighting is enabled. Instead, the equivalent is the material's ambient component. Is this conclusion correct? Thanks
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如果启用了照明，则使用材质颜色（嗯，颜色 - 有几种颜色用于不同类型的光响应）来代替顶点颜色 。材质颜色由
glMaterial*函数指定。如果您想重用代码，可以使用
glEnable(GL_COLOR_MATERIAL)和glColorMaterial(GL_AMBIENT_AND_DIFFUSE)将旧的glColor*调用映射到自动材料颜色。（请尽快切换到着色器 - 着色器方法既简单又更强大）
If the lighting is enabled, then instead of the vertex color, the material color (well, colors - there are several of them for different types of response to light) is used. Material colors are specified by
glMaterial*functions.If you want to reuse your code, you can use
glEnable(GL_COLOR_MATERIAL)andglColorMaterial(GL_AMBIENT_AND_DIFFUSE)to have your oldglColor*calls mapped to material color automatically.(And please switch to shaders as fast as possible - the shader approach is both easier and more powerful)
我想你还没有使用片段着色器。来自 glprogramming.com：
所以是的，不使用顶点颜色。
编辑：您还可以在 GL 规范中查找 GL 闪电方程（您附近有一个，是吗？^^）
I suppose you don't use fragment shader yet. From glprogramming.com:
So yes, vertex color is not used.
Edit: You can also look for GL lightning equation in GL specification (you have one nearby, do you? ^^)