如何编写一个Python程序来读取输入并将其转换为带有海龟图形的预定义14段字符？

发布于 2024-10-02 00:21:57 字数 313 浏览 7 评论 0原文

我已经编写了定义十四个段的海龟图形函数，以及将这些段组装成字符的函数，例如

def MethodA (width) :
   top_stroke(width)    
   middle_stroke(width) 
   left_stroke 
   right_stroke(width)

我已经准备好所有定义，但是如何让python读取输入并将输入的字符转换为我之前定义的十四段形式？

理想情况下，如果我输入“Pizza”，程序应该以十四段形式输出字符“PIZZA”。

任何建议都受到欢迎和赞赏。谢谢，

原文

I have written the turtle graphics functions that define the fourteen segments, and the functions that assemble these segments to form characters, e.g.

def MethodA (width) :
   top_stroke(width)    
   middle_stroke(width) 
   left_stroke 
   right_stroke(width)

I have all the definitions ready, but how do I let python to read an input and convert the characters of the input into the fourteen segments forms, which I defined previously?

Idealy, if I enter "Pizza", the program should produce the output of the characters 'PIZZA' in the fourteen-segments form.

Any suggestions are welcomed and appreciated. Thanks,

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蓝梦月影 2024-10-09 00:21:57

您可以定义一个带有函数引用的字典，如下所示：

Characters = {
    'A': MethodA,
    'B': MethodB,
    # ...
}

然后，对于字符串 s：

s = "Pizza"
for c in s:
    c = c.upper() # to fold lowercase into upper case
    if c in Characters:
        Characters[c](width)

此代码使用 Characters[c] 在字典中查找函数引用，然后 (width) 导致函数被调用（使用 width 参数，正如函数所期望的那样）。

You could define a dictionary with function references like this:

Characters = {
    'A': MethodA,
    'B': MethodB,
    # ...
}

Then, for a string s:

s = "Pizza"
for c in s:
    c = c.upper() # to fold lowercase into upper case
    if c in Characters:
        Characters[c](width)

This code works using Characters[c] to look up the function reference in the dictionary, then the (width) causes the function to be called (with a width parameter, as the function expects).

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