关闭光标的习惯用法

发布于 2024-10-01 23:53:51 字数 540 浏览 10 评论 0原文

我应该使用以下哪两个来确保所有游标都关闭?

    Cursor c = getCursor(); 

    if(c!=null && c.getCount()>0){ 
        try{ 
            // read values from cursor 
        }catch(..){} 
        finally{ 
            c.close(); 
        } 
    }//end if
    

    Cursor c = getCursor(); 
    try{ 
        if(c!=null && c.getCount()>0){ 
            // read values from cursor 
        }//end if 
    }catch(..){
        
    }finally{ 
        c.close(); 
    } 

请指教。

Which of the following two should I be using to make sure that all the cursors are closed?

    Cursor c = getCursor(); 

    if(c!=null && c.getCount()>0){ 
        try{ 
            // read values from cursor 
        }catch(..){} 
        finally{ 
            c.close(); 
        } 
    }//end if
    

OR

    Cursor c = getCursor(); 
    try{ 
        if(c!=null && c.getCount()>0){ 
            // read values from cursor 
        }//end if 
    }catch(..){
        
    }finally{ 
        c.close(); 
    } 

Please advise.

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评论(7

南城追梦 2024-10-08 23:53:51

两者都不是,但第二个最接近。

  • 选项 1 无法正确关闭
    Cursor when getCount() == 0
  • 选项 2 使 finally 块暴露于空指针异常,

我会使用:

Cursor c = getCursor(); 
try { 
    if(c!=null && c.getCount()>0){ 
         // do stuff with the cursor
    }
}
catch(..) {
    //Handle ex
}
finally { 
    if(c != null) {
        c.close(); 
    }
}

...或者如果您希望游标经常为空,您可以稍微扭转一下它:

Cursor c = getCursor(); 
if(c != null) {
    try { 
        if(c.getCount()>0) { 
             // do stuff with the cursor
        }
    }
    catch(..) {
        //Handle ex
    }
    finally { 
        c.close(); 
    }
}

Neither, but the second one was closest.

  • Option 1 doesn't properly close the
    Cursor when getCount() == 0
  • Option 2 leaves the finally block exposed to a null pointer exception

I would use:

Cursor c = getCursor(); 
try { 
    if(c!=null && c.getCount()>0){ 
         // do stuff with the cursor
    }
}
catch(..) {
    //Handle ex
}
finally { 
    if(c != null) {
        c.close(); 
    }
}

... or if you expect the cursor to be null frequently, you could turn it on its head a little bit:

Cursor c = getCursor(); 
if(c != null) {
    try { 
        if(c.getCount()>0) { 
             // do stuff with the cursor
        }
    }
    catch(..) {
        //Handle ex
    }
    finally { 
        c.close(); 
    }
}
若相惜即相离 2024-10-08 23:53:51

这甚至更好:

  • 不使用 c.getCount() - 计数可能需要数据库进行额外的工作,并且不需要
  • 在查询块之前初始化游标,因此创建查询失败后不会跟随finally块

代码:

Cursor c = query(....);
if (c != null) {
   try {        
       while (c.moveToNext()) {  // If empty or after last record it returns false.    
          // process row...
       }
   } 
   finally {
       c.close();
    }
}

请注意,如果出现错误或空游标,c 可能为 null。请参阅https://stackoverflow.com/a/16108435/952135。不过,如果游标为空,我会报告空返回值作为错误。

This is even better:

  • does not use c.getCount() - counting might require extra work for the database and is not needed
  • initialize the cursor before the query block, so failure to create the query is not followed by the finally block

The code:

Cursor c = query(....);
if (c != null) {
   try {        
       while (c.moveToNext()) {  // If empty or after last record it returns false.    
          // process row...
       }
   } 
   finally {
       c.close();
    }
}

Note that c might be null in case of error or empty cursor. See https://stackoverflow.com/a/16108435/952135. I would report null return value in case of empty cursor as a bug, though.

魔法唧唧 2024-10-08 23:53:51

最佳实践如下:

Cursor c = null;    
try {        
   c = query(....);      
   while (c.moveToNext()) {  // If empty or next to last record it returns false.    
      // do stuff..       
   }
} finally {
   if (c != null && !c.isClosed()) {  // If cursor is empty even though should close it.       
   c.close();
   c = null;  // high chances of quick memory release.
}

Best practice is the one below:

Cursor c = null;    
try {        
   c = query(....);      
   while (c.moveToNext()) {  // If empty or next to last record it returns false.    
      // do stuff..       
   }
} finally {
   if (c != null && !c.isClosed()) {  // If cursor is empty even though should close it.       
   c.close();
   c = null;  // high chances of quick memory release.
}
萧瑟寒风 2024-10-08 23:53:51

取决于您要捕获的内容,但我会说第二个,以防万一 c.getCount() 抛出异常。

另外,一些缩进不会出错:)

Depends on what you're catching, but I'd say the second one, just in case c.getCount() throws an exception.

Also, some indentation wouldn't go amiss :)

顾忌 2024-10-08 23:53:51

我会说第一个,主要是因为第二个即使 cnull 也会尝试调用 c.close()。另外,根据文档, getCount()不会引发任何异常,因此无需将其包含在 try 块中。

I'd say the first one, mainly because the second one will try to call c.close() even if c is null. Also, according to the docs, getCount()doesn't throw any exceptions, so there's no need to include it in the try block.

沫雨熙 2024-10-08 23:53:51

我认为我的答案是最好的:

    Cursor cursor = null;

    try {
        cursor = rsd.rawQuery(querySql, null);
        if (cursor.moveToFirst()) {
            do {
                // select your need data from database
            } while (cursor.moveToNext());
        }
    } finally {
        if (cursor != null && !cursor.isClosed()) {
            cursor.close();
            cursor = null;
        }
    }

I think my answer is the best one :

    Cursor cursor = null;

    try {
        cursor = rsd.rawQuery(querySql, null);
        if (cursor.moveToFirst()) {
            do {
                // select your need data from database
            } while (cursor.moveToNext());
        }
    } finally {
        if (cursor != null && !cursor.isClosed()) {
            cursor.close();
            cursor = null;
        }
    }
—━☆沉默づ 2024-10-08 23:53:51

我认为@skylarsutton 是这个问题的正确答案。但是,我想留下问题的代码(答案中的任何代码似乎都有一些缺陷)。请考虑使用我的代码。

Cursor c = query(....);
if (c != null) {
   try {        
       //You have to use moveToFirst(). There is no quarantee that a cursor is located at the beginning.
       for(c.moveToFirst();!c.isAfterLast();c.moveToNext()) {  
          // process row...
       }
   } 
   finally {
       c.close();
    }
}

I think @skylarsutton's is a right answer for the question. However, I want to leave codes for the question (any codes in answers seems to have some flaws). Please consider to use my code.

Cursor c = query(....);
if (c != null) {
   try {        
       //You have to use moveToFirst(). There is no quarantee that a cursor is located at the beginning.
       for(c.moveToFirst();!c.isAfterLast();c.moveToNext()) {  
          // process row...
       }
   } 
   finally {
       c.close();
    }
}
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