三维静态常量数组的初始化
我有一个三维静态常量数组，用作查找表。数组的每个单元格最多可以返回 8 个单独的数字（每个数字是立方体的角 - 准确地说是体素）。例如，MyStaticArray[0][1][1] 可能返回 1,2,5,7。它可以返回单个数字或最多八个数字，如下所示：1,2,3,4,5,6,7,8。
我已经准备好了查找表（在纸上），我的问题是存储它的最佳方式是什么？最初我打算使用 static const unsigned char[][][] 但这显然在这种情况下不起作用，因为表可以返回多个数字（同样，从 1-8 ）。
我的下一个解决方案是返回一个无符号字符数组。即static const unsigned char* [][][]。我如何初始化它（也就是说，如何初始化静态 const 数组以返回给我也是静态的无符号 char 数组，以便我可以在不初始化类的情况下访问它们）？有更好的办法吗？
我希望我能够正确解释这个问题。如果没有，请告诉我，我会尝试重新措辞和/或提供额外信息。
I have a three dimensional static const array that is acting as a lookup table. Each cell of the array can return up to 8 separate numbers (each number is the corner of a cube - a voxel to be exact). So for example, MyStaticArray[0][1][1] might return 1,2,5,7. It can return a single number or a maximum of eight numbers, like so: 1,2,3,4,5,6,7,8.
I already have the lookup table prepared (on paper), my question is what the best way to store it? Initially I was going with a static const unsigned char[][][] but that is obviously not going to work in this case as the table can return more than one number (again, from 1-8).
My next solution was to return an unsigned char array. That is, static const unsigned char* [][][]. How do I initialize this (that is, how do I initialize the static const array to return to me unsigned char arrays that are also static so that I can access them without initializing a class)? Is there a better way?
I hope I was able to explain the question properly. If not, let me know and I will try to reword it and/or provide extra info.
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您可以使用虚拟元素将每个元素填充到最大长度，并使用 4D 数组：
或者您可以使用各个位作为标志，例如：
如果您发现自己需要超过 8 个可能性，请升级到例如
uint16_t< /code> 或uint32_t。使用哪种方法取决于您打算如何处理数据。
You could pad each element up to the maximum length with dummy elements, and go with a 4D array:
or you could use individual bits as flags, e.g.:
If you find yourself needing more than 8 possibilities, upgrade to e.g.
uint16_toruint32_t.Which method you go with depends on what you intend to do with the data.
由于您只返回 8 个可能数字中的 0-8，因此我认为您应该坚持使用
static const unsigned char[][][]并将“数字”存储为单字节位字段，其中位 <如果n是此单元格使用的数字之一，则设置 code>n，因此 fe 1,2,5,7 可能会编码为01010011二进制或 0x53 十六进制。As you only return 0-8 out of 8 possible numbers, I think you should stick with
static const unsigned char[][][]and store the "numbers" as an one byte bitfield where bitnis set ifnis one of the used numbers for this cell, so f.e. 1,2,5,7 might be encoded as01010011binary or0x53hexadecimal.要使用静态初始化，您需要知道数组的每个维度。我想您已经知道这一点，但在您的问题中没有提及，因此我将使用维度 [2][2][2] 作为示例。
您还需要一种方法来确定数组中每个位置的元素数量。您可以将元素的数量作为列表的第一个值，或者创建一个哨兵值来标记列表的末尾。
要将每个列表填充到 8 个元素，它看起来像这样。数组中任何未初始化的值都将设置为 0。
To use static initialization you'll need to know each dimension of your array. I presume you already know this but did not mention it in your question, so I'll use the dimensions [2][2][2] for my examples.
You'll also need a way to determine the number of elements at each position in the array. You can put the number of elements as the first value of the list, or create a sentinel value to mark the end of the list.
To pad each list to 8 elements, it would look like this. Any uninitialized values in the array will be set to 0.