春天 + EntityManagerFactory +Hibernate Listeners +注射
我有一个简单的问题。是否可以通过 @Ressource 或 @Autowired 添加依赖注入到 Hibernate 事件监听器?
我将向您展示我的entitymanagerfactory配置:
<bean id="entityManagerFactory" class="org.hibernate.ejb.EntityManagerFactoryImpl">
<qualifier value="entityManagerFactory" />
<constructor-arg>
<bean
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitManager">
<bean
class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManagerr">
<property name="defaultDataSource" ref="dataSource" />
</bean>
</property>
<property name="dataSource" ref="dataSource" />
<property name="persistenceUnitName" value="mis" />
<property name="persistenceProviderClass" value="org.hibernate.ejb.HibernatePersistence" />
<property name="jpaProperties" ref="jpa.properties" />
<property name="jpaDialect" ref="jpaDialect" />
<property name="jpaVendorAdapter">
<bean
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="generateDdl" value="true" />
<property name="database">
<util:constant
static-field="org.springframework.orm.jpa.vendor.Database.POSTGRESQL" />
</property>
<property name="showSql" value="true" />
</bean>
</property>
</bean>
</constructor-arg>
</bean>
目前我通过jpa.properties注册我的侦听器,
hibernate.ejb.event.load=com.example.hibernate.events.LoadEvent
但在这种情况下,我的侦听器中没有弹簧注入。我找到了一个解决方案,但是这使用了 sessionFactory 而不是实体管理器,我可以在我的上下文中修改 sessionfactory 吗?希望有人有一个好主意或解决方案如何处理这个问题!
非常感谢!
i have a simple question. Its possible to add dependency injection via @Ressource or @Autowired to the Hibernate Eventlistener?
I will show you my entitymanagerfactory configuration:
<bean id="entityManagerFactory" class="org.hibernate.ejb.EntityManagerFactoryImpl">
<qualifier value="entityManagerFactory" />
<constructor-arg>
<bean
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitManager">
<bean
class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManagerr">
<property name="defaultDataSource" ref="dataSource" />
</bean>
</property>
<property name="dataSource" ref="dataSource" />
<property name="persistenceUnitName" value="mis" />
<property name="persistenceProviderClass" value="org.hibernate.ejb.HibernatePersistence" />
<property name="jpaProperties" ref="jpa.properties" />
<property name="jpaDialect" ref="jpaDialect" />
<property name="jpaVendorAdapter">
<bean
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="generateDdl" value="true" />
<property name="database">
<util:constant
static-field="org.springframework.orm.jpa.vendor.Database.POSTGRESQL" />
</property>
<property name="showSql" value="true" />
</bean>
</property>
</bean>
</constructor-arg>
</bean>
At the moment i register my listener via jpa.properties,
hibernate.ejb.event.load=com.example.hibernate.events.LoadEvent
but in this case i have no spring injection in my listener. I found a solution, but this use the sessionFactory and not the entitymanager oder can i modifiy the sessionfactory in my context? Hopefully someone have a nice idea or solutionhow to deal with this problematic!
Big thanks!
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如果您使用 SessionFactory,这将是配置:
但是由于您使用的是 JPA,恐怕您需要按照概述使用 AOP 在此线程中
或者您可以
基类:
现在在您的 lifycycle 方法中首先调用
wireMe()
。更新:
这是 ContextHelper 的示例实现:
将其连接到 Spring Bean 配置中,如下所示:
If you used SessionFactory, this would be the configuration:
But since you are using JPA, I'm afraid you need to use AOP as outlined in this thread
Or you can
Base class:
Now in your lifycycle methods call
wireMe()
first.Update:
Here is a sample implementation of
ContextHelper
:Wire it in your Spring Bean configuration like this: