将 Timerinterval 设置得很快，然后逐渐减慢

发布于 2024-10-01 08:26:37 字数 380 浏览 5 评论 0原文

我有以下代码：

xx=0.50;
[NSTimer scheduledTimerWithTimeInterval:xx target:self selector:@selector(ontimer:) userInfo:nil repeats:YES];

-(void)ontimer
{
    xx=xx+0.05;
    NSTimeInterval dt = [timer timeInterval];
    // do something
}

我想调用 ontimer 0.50 然后 0.55 然后 0.60 &很快。这意味着先快然后逐渐慢。

问题是每次 Time ontimer 都会被调用 0.50 秒。

提前致谢。

原文

i have the following code:

xx=0.50;
[NSTimer scheduledTimerWithTimeInterval:xx target:self selector:@selector(ontimer:) userInfo:nil repeats:YES];

-(void)ontimer
{
    xx=xx+0.05;
    NSTimeInterval dt = [timer timeInterval];
    // do something
}

I want to call ontimer for 0.50 then 0.55 then 0.60 & soon. that means First Fast then gradually slow down.

The Problem is each Time ontimer will be called for 0.50 seconds.

Thanks in Advance.

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彼岸花ソ最美的依靠 2024-10-08 08:26:37

据我所知，当计时器启动时，您无法调整 timeInterval，因此您必须每次都更改 fireDate 。像这样：

- (void)someTimerMethod:(NSTimer *)aTimer {
    static NSTimeInterval pause = 0.5;
    pause += 0.05;
    [aTimer setFireDate:[[[NSDate alloc] initWithTimeIntervalSinceNow:pause] autorelease]];
}

[NSTimer scheduledTimerWithTimeInterval:0.5 target:self selector:@selector(someTimerMethod:) userInfo:nil repeats:YES];

afaik you can't adjust the timeInterval when a timer has been started, so you have to change the fireDate each time. Like this:

- (void)someTimerMethod:(NSTimer *)aTimer {
    static NSTimeInterval pause = 0.5;
    pause += 0.05;
    [aTimer setFireDate:[[[NSDate alloc] initWithTimeIntervalSinceNow:pause] autorelease]];
}

[NSTimer scheduledTimerWithTimeInterval:0.5 target:self selector:@selector(someTimerMethod:) userInfo:nil repeats:YES];

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