在反射 C# 中类变量重置回 null

发布于 2024-10-01 03:04:18 字数 569 浏览 3 评论 0原文

我使用反射创建 Person 类的实例并执行其构造函数，然后执行 person 类的另一个名为“Execute”的函数：

Assembly assembly = Assembly.GetEntryAssembly();
object personObject = assembly.CreateInstance("ReflectionTest.Person");

// Call Constructor
var ctor = personObject.GetType().GetConstructor(new Type[] { typeof(int) });
var obj = ctor.Invoke(new object[] { 10 });

// Call Method
MethodInfo methodInfo = personObject.GetType().GetMethod("Execute");
object obj1 = methodInfo.Invoke(personObject, null);

问题是，当我调用时，我在构造函数中实例化的所有 person 类变量均为 NULL “执行”方法。为什么？我该如何解决这个问题？

原文

i create an instance of a Person class using reflection and execute its constructor and after that i execute another function of the person class called "Execute":

Assembly assembly = Assembly.GetEntryAssembly();
object personObject = assembly.CreateInstance("ReflectionTest.Person");

// Call Constructor
var ctor = personObject.GetType().GetConstructor(new Type[] { typeof(int) });
var obj = ctor.Invoke(new object[] { 10 });

// Call Method
MethodInfo methodInfo = personObject.GetType().GetMethod("Execute");
object obj1 = methodInfo.Invoke(personObject, null);

Th problem is that all the person class variables i instanciated in the constructor ARE NULL when i call the "Execute" method. why ? and how do i get around this?

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小…楫夜泊 2024-10-08 03:04:18

在您的示例中，您使用以下行调用默认构造函数：

object personObject = assembly.CreateInstance("ReflectionTest.Person");

这将是构造对象的正确方法：

Assembly assembly = Assembly.GetEntryAssembly();
Type personType = assembly.GetType("ReflectionTest.Person");
object inst = Activator.CreateInstance(personType, new object[] { 10 });

In your example, you are invoking the default constructor with this line:

object personObject = assembly.CreateInstance("ReflectionTest.Person");

This would be the proper way to construct the object:

Assembly assembly = Assembly.GetEntryAssembly();
Type personType = assembly.GetType("ReflectionTest.Person");
object inst = Activator.CreateInstance(personType, new object[] { 10 });

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